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Top Forums Shell Programming and Scripting Variable won't print out - awk Post 302845097 by alister on Tuesday 20th of August 2013 09:03:15 PM
Old 08-20-2013
You appear to be posting a code fragment. You pass $type to AWK but it is not set anywhere in the preceding script.

You have also neglected to show us the value of $OPTARG and AWK's input.

If you would like competent assistance, show us the complete script, exactly how you're calling it, any input provided to it, the actual output, and the desired output.

Regards,
Alister
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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