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Top Forums Shell Programming and Scripting How to check whether directory has files in it or not in shell script? Post 302807013 by apenkov on Tuesday 14th of May 2013 04:17:51 AM
Code:
CNT=`ls $dir/* | wc -l`
  if [ $CNT -eq 0 ]; then
    echo "There are no files in the dir"
  else
    echo "There are files in the dir"

This User Gave Thanks to apenkov For This Post:
 
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DIR(3)									 1								    DIR(3)

dir - Return an instance of the Directory class

SYNOPSIS
Directory dir (string $directory, [resource $context]) DESCRIPTION
A pseudo-object oriented mechanism for reading a directory. The given $directory is opened. PARAMETERS
o $directory - Directory to open o $context - Note Context support was added with PHP 5.0.0. For a description of contexts, refer to "Streams". RETURN VALUES
Returns an instance of Directory, or NULL with wrong parameters, or FALSE in case of another error. EXAMPLES
Example #1 dir(3) example Please note the fashion in which Directory.read(3)'s return value is checked in the example below. We are explicitly testing whether the return value is identical to (equal to and of the same type as - see Comparison Operators for more information) FALSE since otherwise, any directory entry whose name evaluates to FALSE will stop the loop. <?php $d = dir("/etc/php5"); echo "Handle: " . $d->handle . " "; echo "Path: " . $d->path . " "; while (false !== ($entry = $d->read())) { echo $entry." "; } $d->close(); ?> The above example will output something similar to: Handle: Resource id #2 Path: /etc/php5 apache cgi cli NOTES
Note The order in which directory entries are returned by the read method is system-dependent. PHP Documentation Group DIR(3)

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