[Perl] Different printf formating for different print options
Hi,
Struggling with single quotes, double quotes, etc.
I want to print a header line, followed by lines with actual values, based on a print option.
In real life it is going to be something like 15 print options and 50 values.
Output will be 1 header and several value lines.
In this example I have just 3 print options and 5 values.
Output is just 1 header and one value line.
For some reason I cannot get it working.
I get uninitialized values and quotes where I do not want them.
It expects too many values (seen by the extra comma's in the output).
And therefore I could use some expert help.
Here the example.pl code to make it, hopefully, more clear.
Result:
---------- Post updated at 02:17 PM ---------- Previous update was at 10:08 AM ----------
When I use:
I get the right output:
With:
I get:
Some debugging info:
The 'problem' is that $PrintHeader is seen as 1 string for the printf command.
That is why I get 2 uninitialized values.
---------- Post updated at 03:19 PM ---------- Previous update was at 02:17 PM ----------
This works.
Perhaps not very prety, but it does the job.
Had to use arrays.
And using a string is a bit more easy than using a variable, when working with arrays.
But I am just an amateur.
Always open for suggestion on how to make it more simple.
Hello,
I am trying to output the values in an array to a file. The output needs to be formated such that each array value is left jusified in a field 8 character spaces long. Also, no more than 6 fields on a line. For example:
@array= 1..14;
Needs to be output to the file like so:
1 ... (4 Replies)
Here is the code I'm using
{
printf("%11d %4.2f\% %4.2f\%\n", $1,$2,$3);
}
I want the output to look something like
1235415234 12.24% 52.46%
Instead it looks something like
319203842 42.27\%4.2f\%
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Hi All,
Can anybody tell me why is there a "0" in my output of $date_today ?
#!/usr/local/bin/perl
$date_today = system "date '+%y%m%d'";
print "$date_today\n";
Output:
$ perl test4
080908
0 (3 Replies)
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I wrote a script that does lot of things, and I would like to change the format of a number but without printing it now (so I don't want to use printf as it will print the value immediately).
Schematically here is what I have:
awk 'BEGIN{number=0.01234567}
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Hi,
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I want to print a string say "str1 str2 str3 str4" using printf.
If I try printing it using printf it is printing as follows.
output
-------
str1
str2
str3
str4
btw I'm working in AIX.
This is my first post in this forum :)
regards,
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