sed command to print first instance of pattern in range Post: 302769249

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Top Forums Shell Programming and Scripting sed command to print first instance of pattern in range Post 302769249 by alister on Monday 11th of February 2013 05:07:57 PM

02-11-2013

Registered User

Quote:

Originally Posted by rdrtx1

try:

Code:

sed -n '2,${/10/p; q;}' testFile.txt

Quote:

Originally Posted by in2nix4life

Just add the 'q;' option to quit after the first match:

Code:

sed -n '2,${/10/p;q;}' testFile.txt
two 10

Your suggestions unconditionally abort after reading line 2, and will generate incorrect output if the first instance of matching text within the range does not occur on the first line of that range.

Quote:

Originally Posted by shamrock

Code:

sed -n '/10/ {p;q}' file

This suggestion does not implement the range restriction.

A correct, sed-only solution:

Code:

sed -n '2,${/10/!d; p; q;}'

If the end of the range is not the end of the file, then an additional check is needed to avoid reading the remainder of a long file which does not match. Taking the range to be 2,50:

Code:

sed -ne '2,50{/10/!d; p; q;}' -e '50q'

Regards,
Alister

Last edited by alister; 02-11-2013 at 06:33 PM..

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