Heya,

I'm currently working on a script so I can see which cron jobs, if any, on a system are executing less frequently than 15 minutes (1 - 14 minutes). This is the only data I'm interested in. So far I have the following:

Code:

#!/bin/bash

IFS=$'\n';for line in `ls -f /var/spool/cron/*`;
 do
  echo -e '5\n10\n0\n20' | awk '{if($1 ~ "*" || ($1 ~ /^[0-9]+$/ && $1 != 0) && $1 < 15) print}' <${line};
done

That being said, I'm a bit stuck. That lists the data for minutes, but if a cron job is like so:

5 2 * * * echo "test"

It will still list that cron job, since it's not taking into account the other columns. Is there a decent way to search out only the cron jobs that meet said criteria while excluding those which execute on the hour/day/week?

Any help is appreciated. Thanks!