"umask conundrum"

Post #302670023 by Irishboy24 on Wednesday 11th of July 2012 01:50:33 PM

Full Discussion: umask conundrum
umask conundrum

Hi All,

i was reading up on a umask question on this forum and have a question on this.


the umask value on my home PC running on cygwin is 022. when i create a dir it defaults to permission 755, when i create a file it defaults to 644. Now it starts at 777 for dirs and 666 for files and negate the umask value to get the default permission.


Code:
My question is: i want to change the default file permission create to 755 but without altering the default dir permission. Is this possible ? if so how ?

 
Test Your Knowledge in Computers #480
Difficulty: Easy
Memory addresses are represented using hexadecimal, which is a base-8 counting system.
True or False?

7 More Discussions You Might Find Interesting

1. UNIX Desktop Questions & Answers

Unix Grep Conundrum - Not for Noobies

Help, I have been stuck on this issue for weeks. I am a unix noobie. I have a very long string and within that string I am trying to get proc file names ie PROCNAME1=SOME_FILENAME_UPDTBASE.SQL There is a space on either side. I can't for the life of me peel out the proc name:... (13 Replies)
Discussion started by: owenian
13 Replies

2. Shell Programming and Scripting

Sed pattern space/looping conundrum

Although my sed skills are gradually developing, thanks in large part to this forum, I'm having a hard time dealing with pattern space and looping, which I suspect is what I'll need a better handle on to figure out my current issue, which is converting a multi line file like this: ... (4 Replies)
Discussion started by: tiggyboo
4 Replies

3. Shell Programming and Scripting

Conundrum - Flexible way to strip extension

Hi, First post here. I have something that may prove to be difficult. I have the following files: Example1.0.0.tar.gz Example2.tar Example3.zip Example4.0.0.0.0.0.bzip2 I need to remove the file extensions and store as a variable so they look like this: Example1.0.0 Example2... (3 Replies)
Discussion started by: Spadez
3 Replies

4. Shell Programming and Scripting

sudo scripts conundrum

hello; Got a problem running monitoring scripts using sudo ssh.. Mgmt decided to take away root sudoers access.. so most of the scripts ran as: sudo ssh $BOX ... Now I need to run them as: echo $my_pw | sudo -S -l my_user_id $BOX ... I tried this but not working.. Any wisdom/tricks... (3 Replies)
Discussion started by: delphys
3 Replies

5. Red Hat

Physical Volume Create Conundrum

I want to start by saying I already resolved my issue but I want to understand why I am seeing what I am seeing. I have a server with a RAID controller two 500GB drives and six 600GB drives. The two 500GB drives are mirrored and have the OS installed on them. The six 600GB they wanted set as... (4 Replies)
Discussion started by: scotbuff
4 Replies

6. IP Networking

iptables conundrum

Ok, if youre reading this prepare yourself.(debian based os) so im trying to do this routing with ip tables, i need to forward/SNAT traffic from 192.168.111.1 to 10.10.10.250, the 192.x.x.x ips are being shoved into a honeyd like program called inetsim so its offline, 10.10.10.125 is connected... (3 Replies)
Discussion started by: Shocco
3 Replies

7. OS X (Apple)

Help in explaining this echo conundrum.

OSX 10.12.3, default bash terminal. Consider this code and note it is calling 'sh' inside the code... #!/bin/sh echo '1\n2\n2\n3\n5' > /tmp/text hexdump -C /tmp/text /bin/echo '1\n2\n3\n4\n5' > /tmp/text hexdump -C /tmp/text Now view the interactive mode below, note the underlying shell is... (6 Replies)
Discussion started by: wisecracker
6 Replies
UMASK(2)						     Linux Programmer's Manual							  UMASK(2)

NAME
umask - set file mode creation mask SYNOPSIS
#include <sys/types.h> #include <sys/stat.h> mode_t umask(mode_t mask); DESCRIPTION
umask() sets the calling process's file mode creation mask (umask) to mask & 0777 (i.e., only the file permission bits of mask are used), and returns the previous value of the mask. The umask is used by open(2), mkdir(2), and other system calls that create files to modify the permissions placed on newly created files or directories. Specifically, permissions in the umask are turned off from the mode argument to open(2) and mkdir(2). The constants that should be used to specify mask are described under stat(2). The typical default value for the process umask is S_IWGRP | S_IWOTH (octal 022). In the usual case where the mode argument to open(2) is specified as: S_IRUSR | S_IWUSR | S_IRGRP | S_IWGRP | S_IROTH | S_IWOTH (octal 0666) when creating a new file, the permissions on the resulting file will be: S_IRUSR | S_IWUSR | S_IRGRP | S_IROTH (because 0666 & ~022 = 0644; i.e., rw-r--r--). RETURN VALUE
This system call always succeeds and the previous value of the mask is returned. CONFORMING TO
SVr4, 4.3BSD, POSIX.1-2001. NOTES
A child process created via fork(2) inherits its parent's umask. The umask is left unchanged by execve(2). The umask setting also affects the permissions assigned to POSIX IPC objects (mq_open(3), sem_open(3), shm_open(3)), FIFOs (mkfifo(3)), and Unix domain sockets (unix(7)) created by the process. The umask does not affect the permissions assigned to System V IPC objects created by the process (using msgget(2), semget(2), shmget(2)). SEE ALSO
chmod(2), mkdir(2), open(2), stat(2) COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. Linux 2008-01-09 UMASK(2)

Featured Tech Videos

All times are GMT -4. The time now is 11:30 AM.
Unix & Linux Forums Content Copyright 1993-2019. All Rights Reserved.
Privacy Policy