okay so i run an openssl command to get the date of an expired script. Doing so gives me this:
Then i cut everything out and just leave the month which is "Jun"
Now the next part of my script is to tell the user if the the certificate is expired or not and to do that i use an if statement in which it looks like this:
I can't figure out how to convert the month into an integer to even do the comparison. I thought of doing the brute force way which is this:
Clearly that's a terrible way to do it. Does anyone know what i can do?
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Hi ...
I am trying to calculate the time needed for a command to execute..
but the resulting value is getting as string..
so i am not able to use "expr " command..
please help me to convert the value to integer so that i can proceed with my script..
Regards
esham (1 Reply)
Hi all,
I'm trying to convert a decimal number into an integer number; I'm doing this:
n=`echo |awk '{ print "'"$mem"'"*10}'`
where the variable mem is equal to 3.7
I'd like to obtain 37, but the expression above gives me 30.
Help please!!!!
thx a lot (4 Replies)
Hi,
I am passing a variable to a unix function.
However when I try to assign the value to another variable like
typeset -i I_CACHE_VAL=$2
Is this because of String to Integer conversion?
I get an error.
Please help me with thsi.
Thanks (2 Replies)
Hi everyone,
I would like to know how to convert an integer to a string. for instance if i=1 i would like to creat a variable called constant1. i want to do this in a for loop so for each value of i, i create a new variable such as constant2, constant3,... and so on.
for i in 1 2 3
do ... (1 Reply)
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The problem is that myduration variable is not an integer. How do I convert it to integer?
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Dear community,
i got a problem to get "date +%j" as the right value.
Today is the 10th day of the year.
#./script.sh 2
#!/bin/bash/
Var1=$(date +%j)
Var2=$1
let result=$Var1+$Var2
echo $Var1 plus $Var2 equals $result
The output of the script is:
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Hi guys,
I'm new here. I have a problem at work. One of our scripts was eventually having a bug and only detected recently. Here's the issue and background:
Bash Script which calls AWK script
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Hello,
How can we convert date like format 20181004171050 in seconds ?
I can able to convert till date but failing for HHMMSS.
date -d "20181004" "+%s" output as 1538596800 .
But when i add hhmmss it is failing date -d "20181004172000" "+%s" result Invalid date
Kindly guide.
Regards (16 Replies)
Hi Folks -
Linux Version = Linux 2.6.39-400.128.17.el5uek x86_64
I have a process that determines the start and end load periods for an Oracle data load process.
The variables used are as follows follows:
They are populated like such:
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