Date Vadidation in YYYY-MM-DD
Hi ,
Please, Help me in validating given date that is passed in arg as YYYY-MM-DD.
It should cover
check 1 <= DD <= 31 and 1 <= MM <= 12
for each mm check 1 <=DD<= {28,30,31} (depending)
for someYYYY and MM== 02 check 1 <= dd <= 29
I the... (1 Reply)
I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
Dear all,
I have 2 questions.
I have a file with many rows which has date of the format YYYYMMDD.
1. I need to change the date to that weeks friday date(Ex: 20120716(monday) to 20120720). Satuday/Sunday has to be changed to next week friday date too.
2. After converting the date to... (10 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am changing epoch times to dates. I was able to do the following:
echo "$varx" | gawk '{print strftime("%c", $0)}'
Mon Dec 31 16:26:40 2012
This changes the epoch date (which is what varx is) into localtime.
However, my problem is that I only want 12/31/2012 and not the Mon Dec 31... (2 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)