Script to find & replace a multiple lines string across multiple php files and subdirectories
Hey guys. I know pratically 0 about Linux, so could anyone please give me instructions on how to accomplish this ?
The distro is RedHat 4.1.2 and i need to find and replace a multiple lines string in several php files across subdirectories.
So lets say im at root/dir1/dir2/ , when i execute the script it should search and replace a piece of code on php files inside this directory and its subdirectories.
The closest i found i think it was this:
But the string i need to find and replace have multiple lines, so i dont know how to put it in this script.
Also i dont know how to save and execute this script
EDIT: AH and by the way, i need to only DELETE the piece of code from these PHP files, i dont need to replace it with something else...
Could anyone please give me detailed instructions on this ?
hi guys,
Suppose you have 100 files in a folder and you want to replace all occurances of a word say "ABCD" in those files with "DCBA", how would you do
it ???
jatin (13 Replies)
I used the following script
cd pathname
for y in `ls *`;
do sed "s/ABCD/DCBA/g" $y > temp; mv temp $y;
done
and it worked fine for finding and replacing strings with names etc. in all files of the given path.
I'm trying to replace a string which consists of path (location of file)
... (2 Replies)
i have to search a string and replace with multiple lines.
example
Input
echo 'sample text'
echo 'college days'
output
echo 'sample text'
echo 'information on students'
echo 'emp number'
echo 'holidays'
i have to search a word college and replace the multiple lines
i have... (1 Reply)
I used the following script
cd pathname
for y in `ls *`;
do sed "s/ABCD/DCBA/g" $y > temp; mv temp $y;
done
and it worked fine for finding and replacing strings with names etc. in all files of the given path.
I'm trying to replace a string which consists of path (location of file)
... (11 Replies)
find . -type f -name "*.sql" -print|xargs perl -i -pe 's/pattern/replaced/g'
this is simple logic to find and replace in multiple files & folders
Hope this helps.
Thanks
Zaheer (0 Replies)
Hi,
I am creating a script to do a find and replace single/multiple lines in a file with any number of lines.
I have written a logic in a script that reads a reference file say "findrep" and populates two variables $FIND and $REPLACE
print $FIND gives
Hi How r $u
Rahul()
Note:... (0 Replies)
Can someone tell me how I can do this?
e.g:
a=$(echo -e wert trewt ertert ertert ertert erttert
erterte
rterter
tertertert
ert)
How do i replace the STRING with $a?
I try this:
sed -i 's/STRING/'"$a"'/g' filename.ext
but this don' t work (2 Replies)
I have a list of files all over a file system e.g.
/home/1/foo/bar.x
/www/sites/moose/foo.txtI'm looking for strings in these files and want to replace each occurrence with a replacement string, e.g.
if I find: '#@!^\&@ in any of the files I want to replace it with: 655#@11, etc.
There... (2 Replies)
Hello Guys,
I need to replace a string with multiple lines.
For eg:-
ABC,DEF,GHI,JKL,MNO,PQR,STU
need to convert the above as below:-
ABC,DEF,
GHI1
GHI2
GHI3,
JKL,MNO,
PQR1
PQR2
PQR3,
STU
i have tried using code as:- (2 Replies)
Discussion started by: jassi10781
2 Replies
LEARN ABOUT PHP
echo
ECHO(3) 1 ECHO(3)echo - Output one or more stringsSYNOPSIS
void echo (string $arg1, [string $...])
DESCRIPTION
Outputs all parameters.
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other
language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want
to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn-
tax only works with the short_open_tag configuration setting enabled.
I have <?=$foo?> foo.
PARAMETERS
o $arg1
- The parameter to output.
o $...
-
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
echo examples
<?php
echo "Hello World";
echo "This spans
multiple lines. The newlines will be
output as well";
echo "This spans
multiple lines. The newlines will be
output as well.";
echo "Escaping characters is done "Like this".";
// You can use variables inside of an echo statement
$foo = "foobar";
$bar = "barbaz";
echo "foo is $foo"; // foo is foobar
// You can also use arrays
$baz = array("value" => "foo");
echo "this is {$baz['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
echo 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just echo variables
echo $foo; // foobar
echo $foo,$bar; // foobarbarbaz
// Some people prefer passing multiple parameters to echo over concatenation.
echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10);
echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . "
";
echo <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon. no extra whitespace!
END;
// Because echo does not behave like a function, the following code is invalid.
($some_var) ? echo 'true' : echo 'false';
// However, the following examples will work:
($some_var) ? print 'true' : print 'false'; // print is also a construct, but
// it behaves like a function, so
// it may be used in this context.
echo $some_var ? 'true': 'false'; // changing the statement around
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO print(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group ECHO(3)