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Top Forums UNIX for Dummies Questions & Answers extract columns using grep or regular expressions Post 302591174 by quextil on Wednesday 18th of January 2012 06:25:34 PM
Old 01-18-2012
extract columns using grep or regular expressions

I am trying to print columns from a table whose name (header) matches a certain string.

E.g.,

patient1001 patient1002 patient2005 patient3005 patient4001
0 0 0 0 0
2 9 2 8 3
2 7 3 0 2

Say I want to print columns whose names end with "01"

patient1001 patient4001
0 0
2 3
2 2

I tried:

awk '{ for (i=1; i<=NF; i++) {if ($i ~ /01$/); print $i; }}' file > file.txt

but that failed. Thanks!
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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