08-07-2011
Quote:
But i suspect that the below command always return 0 as status code regardless of the string "Job Status : RUN FAILED (3)" in the output:
Quote:/opt/app/dstage/DataStage752/Ascential/DataStage/DSEngine/bin/dsjob -server servername -user uname -password pwd -jobinfo $job_name | grep "Job Status : RUN FAILED (3)"
so $? always equals to 0 and all the jobs will be written into file.
The grep command should always exit with a non-zero code if the string was not found in the input text. Are you executing any commands between the grep and your if statement? If so, the $? value will be replaced with the value from that command and might thus always appear to be zero. Ensure that your if statement is immediately following the statement with grep. If it is, and you are still having problems, please post the whole script (it looks like you cut bits and pieces in your original post).
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)