Grep empty space and sort Post: 302529698

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I need to pass an empty space in the command ="java ......... " as one of the arguments where java calls some java command.... (It accepts it in windows as " ") Thanks in advance SD

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Given a csv file with 40 columns with name, address, hometown etc. I use a bash command in 1 line which: 1. gets the address column and pipes that to 2. grep the first digit and everything that follows Command: awk -F ";" '{print $19}' /Users/jb/Desktop/ReorderTempTotal.csv | grep -o "\d.*"...

LEARN ABOUT MINIX

grep

GREP(1) 						      General Commands Manual							   GREP(1)

NAME

       grep - search a file for lines containing a given pattern

SYNOPSIS

       grep [-elnsv] pattern [file] ...

OPTIONS

       -e     -e pattern is the same as pattern

       -c     Print a count of lines matched

       -i     Ignore case

       -l     Print file names, no lines

       -n     Print line numbers

       -s     Status only, no printed output

       -v     Select lines that do not match

EXAMPLES

       grep mouse file	   # Find lines in file containing mouse

       grep [0-9] file	   # Print lines containing a digit

DESCRIPTION

       Grep  searches  one  or	more  files (by default, stdin) and selects out all the lines that match the pattern.  All the regular expressions
       accepted by ed and mined are allowed.  In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or  1
       occurrences,  and  |  can  be used between two regular expressions to mean either one of them.  Parentheses can be used for grouping.  If a
       match is found, exit status 0 is returned.  If no match is found, exit status 1 is returned.  If an error is detected,  exit  status  2	is
       returned.

SEE ALSO

       cgrep(1), fgrep(1), sed(1), awk(9).

																	   GREP(1)

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Discussion started by: JosephGerard

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Help required on printing the line if third field is not a empty space

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Grep for empty file

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