Let's say I write a simple script that contains the following:
date | awk '{print $1}'
date | awk '{print $2}'
Of course, when I run the script the output will look similar to:
Tue
Mar
What if I want my ouput to be on one line as follows:
Tue Mar
What changes would I need to... (2 Replies)
I have a file in CSV format (2 columns ID and Number of Items):
AB1 ,,10
AB2 ,,20
AB2 ,, 30
AB3 ,, 10
AB4 ,, 20
AB4 ,, 30
AB4 ,, 40
AB5 ,, 50
AB6 ,, 10
AB7 ,, 20
AB7 ,, 30
AB7 ,, 40
......
This file is produced daily i would like to get it in the following format, so... (6 Replies)
Hello,
I have got the following kine in my script
awk '{printf("%s,", $0);next}{printf("%s", $0)}' ORS="," a.txt > b.out
The contents of b looks somewaht like this:
QUEUE(QUEUE1.Q),CURDEPTH(0),QUEUE(QUEUE2.Q),CURDEPTH(0),QUEUE(QUEUE3.Q),CURDEPTH(0)
But my desired output is :... (10 Replies)
# echo $PATH
/usr/kerberos/sbin:/usr/kerberos/bin:/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin
How would i write a script to display permission on each folders in $PATH variable below format.
drwxr-xr-x 2 0 root 4096 Nov 24 14:51 /usr/kerberos/sbin
drwxr-xr-x 2 0... (2 Replies)
Hi I have a file as given below:
<table border=1>
<TR><TH>Script Name</TH><TH>CVS Status</TH><TH>Script Location</TH></TR>
<TR><TD><CENTER>Work Area: /home/ustst/</CENTER></TD></TR>
<TR><TD><CENTER>admin_export.sh</CENTER></TD><TD><CENTER>Locally... (1 Reply)
Hi all,
Below is my testfile:
COST,31-MAR-2011 01:01:04,31-MAR-2011 11:22:12,622
COST,21-MAR-2011 22:00:20,22-MAR-2011 11:07:23,788
FARE,23-MAR-2011 22:00:22,24-MAR-2011 10:10:46,731
FARE,02-MAR-2011 14:01:50,03-MAR-2011 08:30:54,1110
I need to append a number, for example 700, to the... (2 Replies)
when i try this awk its giving out put as below.
awk '!(/^$/||/--/||/selected/||/^ *$/){print $1}' tmp.txt
output
=====
1
2010-08-03-12.31.26.126000
how excluede the 1st line ? i mean i want output only 2nd line i.e 2010-08-03-12.31.26.126000; (5 Replies)
Our vendor produces a report that I would like to format in a particular way.
Here is the sample output from their report:
# AA.INDEX 2 11 2 239 52 (7,2) 07 MAY 11 203.1 55
# ACCOUNT 2 89561 2 ... (4 Replies)
Hi all,
I'm writing a simple awk code:
awk 'BEGIN {FS="|"};{print "Type\tNumber\ttypes\tTotal";};{print $1, "\t", $2, "\t", $3, "\t", $4, "\t";}' db_query.txt
it gives me the result:
Type Number types Total
XXX 498.0 5100.0 5274.661
Type Number types Total... (7 Replies)
i would like to format the 9 character with suffix as "0".
i tried below it doesn't work.
>a=12345
> echo $a | awk '{printf "%-09s\n",$1}'
>12345
required output is 123450000
can you guys help me out ? (7 Replies)
Discussion started by: expert
7 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)