I'm not 100% sure what you're doing in that regex but remember that * has a slightly different meaning in a regex than it does in shell globbing. In a shell, * means "match zero or more of any character". In a regex it means "match zero or more of the previous character". So [0-8]* tells it to match zero or more characters in the set 0-8. Also, in a regex, . is a special character meaning "any character".
So I think you could do:
which will match anything for the first three chars, then only even numbers for the last digit.
ok but point is "i need to get evenly line numbers"
same number mixed string combination can be placed any where in any line
3461:1.D. The copyright laws of the place where you are located also govern
what i need is get the line number 3461 from a line only if it s an even number!
---------- Post updated at 11:59 AM ---------- Previous update was at 11:56 AM ----------
[/CODE]if this is what you want, you could
[/QUOTE]
Maybe this question is out there, but I searched and didnt see it.
To print my files I use
more filename | lpr -Pprinter
I would like to print my scripts with line numbers.
How do I do this? (2 Replies)
Hello..
I have got one file ...
I want to add line numbers with space form starting to ending..
for example...if the file is
--------------------------
sand sorcd 2345 345
recds 234 234 5687
yeres 568 988 erfg4 67
--------------------------
I need the output
... (4 Replies)
Hi i would like to add line numbers to end of each line in a file.
I am able to do it in the front of each line using sed, but not able to add at the end of the file.
Can anyone suggest
The following code adds line number to start of each line
sed = filename | sed 'N;s/\n/\t/'
how can i... (5 Replies)
Hi all experts,
I am getting error in my shell scripts and i want to find out which lines is in errors. How i can display the line numbers . Is it NU command? Please give me some suggestions. (4 Replies)
Hi all,
I have a file consisting of lines in such a format: separated by space and M1 EOS for fullstop (.) ]
e.g
M1 I
M1 have
M1 a
M1 file
M1 consisting
M1 of
M1 lines
M1 in
M1 such
M1 a
M1 format
M1 EOS
M2 This
M2 is
M3 an (4 Replies)
I know if i use grep -n that the output will have the lines numbered but is there a way to grep the actually line number.
so like this
grep -n "one" /usr/dict/numbers
1:one
21:twenty-one
31:thirty-one
41:forty-one
51:fifty-one
61:sixty-one
71:seventy-one
81:eighty-one
91:ninety-one
... (1 Reply)
Hi! I'm trying to assign line numbers to each line of the file
for example consider the following..
The contents of the input file are
hello how are you?
I'm fine.
How about you?
I'm trying to get the following output..
1 hello how are you?
2 I'm fine.
3 How about you? ... (8 Replies)
hi,
I need some unix command to replace the following thing. The line shuld start with oly numbers. If it starts with anything other than number it shuld be taken back to the last line.
My file:
1234|test
weye|test1|break
576|test|break|title
2369|test|line|break
tite|break... (7 Replies)
Hello All,
I am very sure this a dumb question to many, but from my view its worth asking.
When I do a vi on a file, on the right bottom side I am seeing something like below:
27,16-24 7%
which tells me that I am on line 27 (which is the first number before the comma, i would like... (11 Replies)
Discussion started by: babyPen1985
11 Replies
LEARN ABOUT X11R4
regex
regex(1F) FMLI Commands regex(1F)NAME
regex - match patterns against a string
SYNOPSIS
regex [-e] [ -v "string"] [ pattern template] ... pattern [template]
DESCRIPTION
The regex command takes a string from the standard input, and a list of pattern / template pairs, and runs regex() to compare the string
against each pattern until there is a match. When a match occurs, regex writes the corresponding template to the standard output and
returns TRUE. The last (or only) pattern does not need a template. If that is the pattern that matches the string, the function simply
returns TRUE. If no match is found, regex returns FALSE.
The argument pattern is a regular expression of the form described in regex(). In most cases, pattern should be enclosed in single quotes
to turn off special meanings of characters. Note that only the final pattern in the list may lack a template.
The argument template may contain the strings $m0 through $m9, which will be expanded to the part of pattern enclosed in ( ... )$0 through
( ... )$9 constructs (see examples below). Note that if you use this feature, you must be sure to enclose template in single quotes so
that FMLI does not expand $m0 through $m9 at parse time. This feature gives regex much of the power of cut(1), paste(1), and grep(1), and
some of the capabilities of sed(1). If there is no template, the default is $m0$m1$m2$m3$m4$m5$m6$m7$m8$m9.
OPTIONS
The following options are supported:
-e Evaluates the corresponding template and writes the result to the standard output.
-v "string" Uses string instead of the standard input to match against patterns.
EXAMPLES
Example 1: Cutting letters out of a string
To cut the 4th through 8th letters out of a string (this example will output strin and return TRUE):
`regex -v "my string is nice" '^.{3}(.{5})$0' '$m0'`
Example 2: Validating input in a form
In a form, to validate input to field 5 as an integer:
valid=`regex -v "$F5" '^[0-9]+$'`
Example 3: Translating an environment variable in a form
In a form, to translate an environment variable which contains one of the numbers 1, 2, 3, 4, 5 to the letters a, b, c, d, e:
value=`regex -v "$VAR1" 1 a 2 b 3 c 4 d 5 e '.*' 'Error'`
Note the use of the pattern '.*' to mean "anything else".
Example 4: Using backquoted expressions
In the example below, all three lines constitute a single backquoted expression. This expression, by itself, could be put in a menu defini-
tion file. Since backquoted expressions are expanded as they are parsed, and output from a backquoted expression (the cat command, in this
example) becomes part of the definition file being parsed, this expression would read /etc/passwd and make a dynamic menu of all the login
ids on the system.
`cat /etc/passwd | regex '^([^:]*)$0.*$' '
name=$m0
action=`message "$m0 is a user"`'`
DIAGNOSTICS
If none of the patterns match, regex returns FALSE, otherwise TRUE.
NOTES
Patterns and templates must often be enclosed in single quotes to turn off the special meanings of characters. Especially if you use the
$m0 through $m9 variables in the template, since FMLI will expand the variables (usually to "") before regex even sees them.
Single characters in character classes (inside []) must be listed before character ranges, otherwise they will not be recognized. For exam-
ple, [a-zA-Z_/] will not find underscores (_) or slashes (/), but [_/a-zA-Z] will.
The regular expressions accepted by regcmp differ slightly from other utilities (that is, sed, grep, awk, ed, and so forth).
regex with the -e option forces subsequent commands to be ignored. In other words, if a backquoted statement appears as follows:
`regex -e ...; command1; command2`
command1 and command2 would never be executed. However, dividing the expression into two:
`regex -e ...``command1; command2`
would yield the desired result.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO awk(1), cut(1), grep(1), paste(1), sed(1), regcmp(3C), attributes(5)SunOS 5.10 12 Jul 1999 regex(1F)