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Top Forums Shell Programming and Scripting Concatenate lines between lines starting with a specific pattern Post 302465498 by Scrutinizer on Friday 22nd of October 2010 03:12:00 PM
Old 10-22-2010
Try this:
Code:
awk '{printf (/>/)?RS"%s"RS:"%s",$0}END{print x}' infile

your code does not work because of this:
Code:
substr($0,1,1)

This User Gave Thanks to Scrutinizer For This Post:
 

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Regexp(3I)						    InterViews Reference Manual 						Regexp(3I)

NAME
Regexp - regular expression searching SYNOPSIS
#include <InterViews/regexp.h> DESCRIPTION
A Regexp encapsulates a regular expression pattern and defines operations for searching and matching the pattern against a string. The syntax of the regular expression pattern is the same as that for ed(1). Information can be obtained about the most recent match of the regular expression (and its sub-expressions). PUBLIC OPERATIONS
Regexp(const char* pattern) Regexp(const char* pattern, int length) Construct a new Regexp for pattern. int Match(const char* text, int length, int index) Attempt a match against text (of length length) at position index. The return value is the length of the matching string, or a neg- ative number if the match failed. int Search(const char* text, int length, int index, int range) Search for a match in the string text (of length length). Matches are attempted starting at positions between index and index plus range. If range is positive the first match after index is reported. If range is negative the first match before index is reported. The return value is the index of the starting position of the match, or a negative number if there is no match in the specified range. int BeginningOfMatch(int subexp) int EndOfMatch(int subexp) Return information about the most recent match. If subexp is zero (the default), information is reported for the complete regular expression. Other values of subexp refer to sub-expressions in the pattern. For example, if subexp is 2, information is returned for the sub-expression specified by the second pair of ( and ) delimiters in the pattern. SEE ALSO
ed(1) InterViews 23 May 1989 Regexp(3I)
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