08-20-2010
awk/sed percentage calculation
Hi all
i have a text file with columns delimited with ,
2010-08-18,10,24,.09751,39,7,14872,26732
.
.
.
i would to add a extra column in the end with percentage calculation of columns 5 and 8 ie (39/26732)*100
so the output must look like
2010-08-18,10,24,.09751,39,7,14872,26732,.14
.
.
.
Thanks
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COLRM(1) BSD General Commands Manual COLRM(1)
NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO
awk(1), column(1), cut(1), paste(1)
HISTORY
The colrm command appeared in 3.0BSD.
BSD
August 4, 2004 BSD