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Top Forums UNIX for Dummies Questions & Answers Problem with sort-of array in SH Post 302414242 by onstock on Monday 19th of April 2010 03:04:41 PM
Old 04-19-2010
jsmoriss,

Thank you for your fast reply!

Your example works, but as I mentioned in my first post, I have troubles with printing out values:

Quote:
All I could achieve was printing out the number of $n which was storing information.
Code:
for val in $*
do
        eval var$n="$val"
        n="`expr $n + 1`"
        echo $val$n
done

And the result is:

Code:
hallerx@ktl ~ $ sh dir1 10 5 9
1
2
3

I am sure I'm calling the output in a wrong way (echo line). How could I print out the values stored in this array?

Thanks for your help Smilie
 

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