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Top Forums Shell Programming and Scripting Subtracting columns against each other Post 302398730 by pludi on Thursday 25th of February 2010 11:48:57 AM
Old 02-25-2010
You do know that with your requirements you'll get n^2 columns of output for any n columns of input (5 columns input -> 25 cols output, 1.000 input -> 1.000.000 output)

That aside, try if this fits you:
Code:
#!/usr/bin/perl -W

use strict;
use warnings;

while ( my $line = <DATA> ) {
    my @cols = split / /, $line;
    my ( $l, $r ) = ( 0, 0 );
    for ( $l = 0 ; $l <= $#cols ; $l++ ) {
        for ( $r = 0 ; $r <= $#cols ; $r++ ) {
            print $cols[$l] - $cols[$r], " ";
        }
    }
    print "\n";
}

__DATA__
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5

Exemplary output:
Code:
$ perl cols.pl
0 -1 -2 -3 -4 1 0 -1 -2 -3 2 1 0 -1 -2 3 2 1 0 -1 4 3 2 1 0 
0 -1 -2 -3 -4 1 0 -1 -2 -3 2 1 0 -1 -2 3 2 1 0 -1 4 3 2 1 0 
0 -1 -2 -3 -4 1 0 -1 -2 -3 2 1 0 -1 -2 3 2 1 0 -1 4 3 2 1 0 
0 -1 -2 -3 -4 1 0 -1 -2 -3 2 1 0 -1 -2 3 2 1 0 -1 4 3 2 1 0 
0 -1 -2 -3 -4 1 0 -1 -2 -3 2 1 0 -1 -2 3 2 1 0 -1 4 3 2 1 0


Last edited by pludi; 02-25-2010 at 12:50 PM.. Reason: typo
 

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