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Top Forums Shell Programming and Scripting How to print exit status in AWK Post 302377762 by Pauline mugisha on Saturday 5th of December 2009 04:04:16 AM
Old 12-05-2009
$ #!/bin/nawk -f
$ BEGIN { FS=",";

$ if (ARGC ==1)
$ {print "You need 2 arguments on the command line"}
$ echo "Error" | awk '{exit 13}'
$ echo $?

$ }

How do i have an exit status returned when the number of commandline arguments is 1. The above script does not work
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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