Hi Guru's,
I need to create 3 files with the contents "ABC" using single command.
Iam using:
echo "ABC" > file1.txt file2.txt file3.txt
the above command is not working. pls help me...
With Regards / Ganapati (4 Replies)
I have two text files, each of then only containing ONE line and NO carraige return or white space at the end...how do I echo both of these text files to the screen without putting an extra line? I want to do this from the command line.
file1.txt:
this is file1.txt 1
file2.txt:
this is... (4 Replies)
Hello, this is my first post and question. I have search before for this problem but didn't find anything similar.
My case: I have a string inside the variable string1 like this:
string1="lala lele lili lolo lulu"
When I do echo of it, it appears like this:
echo $string1
lala lele lili... (8 Replies)
for i in `cat /export/home/afahmed/Arrvial_time.txt`
do
echo $i
echo $i | awk '$3 < $D { print $4 }' >> dynamic_DF.txt;
done
When i echo, its echo as
Nov
15
02:24
/export/home/pp_adm/inbound//wwallet_20111115.txt where i expect it to be Nov 15 02:24... (7 Replies)
Hello
i tried many times echo $variables into text file with no success
for example:
echo "#!/bin/sh
BBHTAG=RFOCLT_check # What we put in bb-hosts to trigger this test
COLUMN=RFOCLT # Name of the column, often same as tag in bb-hosts
$BBHOME/bin/bbhostgrep $BBHTAG | while read... (5 Replies)
Hi all, I am trying to create a script to read my Windows UUIDs and create mounts in fstab. I know there are different and maybe even better ways to mount Windows partitions at boot time, but I always manually create them in fstab successfully. I do a clean install of Ubuntu often and would like to... (2 Replies)
so...
Lets assume I have a text file.
The text file contains multiple "#" symbols.
I want to replace all thos "#"s with a STRING using DOS/Batch
I want to add a certain TEXT to the end of each line.
How can I do this WITHOUT aid of sed, grep or anything linux related ? (1 Reply)
$cat FILE.txt
$PATH1/file1.txt
$PATH2/file2.txt
where$PATH 1 = /root/FILE_DR/file1.txt
$PATH 2 = /root/FILE_DR/file2.txt
for I in `cat FILE.txt`
do
v=`echo $I`
echo $v
if
then
rm $v (5 Replies)
HI
I have and echo command which works perfectly in the shell but when i execute in the script it gives me an error code
query is as below
QUERY=`echo "Select Severity,Dupl_count,Creation_Time,Last_Received,Node_Name,Node_Name,Object,Message_Group,Message_Text,Last_Annotation from " \
... (2 Replies)
Hi dears
i use bash shell
i have INPUT.txt
like this
number of columns different in one
some row have 12 , some 11 columns
see last column
INPUT.txt
CodeGender Age Grade Dialect Session Sentence Start End Length Phonemic Phonetic
63 M 27 BS/BA TEHRANI 3 4 298320 310050... (2 Replies)
Discussion started by: alii
2 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)