Hello
I am executing the following script
nawk 'NR == 1 || substr($0,63,5) ~ /H... / && \
_++ == 2 { fn && close(fn); fn = "part_" ++c; _ = 1 }
{ print > fn }' sample.dat
When i execute as it is it is executing fine. but when i execute the whole script as a single line like below
... (2 Replies)
Hi ,
I m getting an error after executing the script.
My script.
Script is used to find out the date on 8 different machines(mentioned in SERVERNAMES file).
I have added public key to avoid ssh password and ssh without password working fine.
#!/bin/sh
fn_VMFind()
{
Date=`ssh -t... (5 Replies)
Hi
Please assist. Im getting an error while execuing the script name d "cdsnd.basel.cd_new
" as siiadm user. Thanks.
siiadm> ls -l
total 64
-rwxr-xr-x 1 siiadm sboadm 1004 Sep 17 2008 cdsnd.basel.cd
-rwxr-xr-x 1 siiadm sapsys 998 Nov 16 09:14 cdsnd.basel.cd_new... (1 Reply)
Hi,
I am not able to figure out what the problem is:
getting the following error
sqltst.sh: 1: not found
here is the script
#!/bin/sh
. /home/dev1/.profile
. /home/dev1/.infenv
`sqlplus -s $REPDB_LOGON << EOF
SET SERVEROUT ON
SET FEEDBACK OFF
SET HEADING OFF
SET TRIMSPOOL... (4 Replies)
hi all,
i am getting libssh2 error while executing script in RHEL 6, when i locate that file its not there below is the ouput of this
# locate libssh2_agent_init
# cat /etc/issue
Red Hat Enterprise Linux Server release 6.1 (Santiago)
Kernel \r on an \m
how do i resolve this issue, i... (1 Reply)
I have the following script test.sh owned by dwdev account and group dwdev, the permissions on the script are as follows.
-rw-r-x--- 1 dwdev dwdev 279 Sep 17 13:19 test.sh
Groups:
cat /etc/group | grep dwdev
dwdev:x:704:dwdev
dwgroup:x:725:dwdev
writers:x:726:dwdev
User:
cat /etc/passwd |... (3 Replies)
getting error as below while executing script in linux.
OS version:
Linux VGP-3GPSDB-LX 3.10.0-514.el7.x86_64 #1 SMP Wed Oct 19 11:24:13 EDT 2016 x86_64 x86_64 x86_64 GNU/Linux
./imxtract.sh: line 395: unexpected EOF while looking for matching ``'
./imxtract.sh: line 402: syntax error:... (1 Reply)
Hi,
I wrote this script to test if the output for DIR1 and DIR2 comes out as I want :
#!/bin/bash
DAY=$(date +%d)
MONTH=$(date +%b)
YEAR=$(date +%Y)
DIR1=$($MONTH$YEAR"_Blast_BC01")
DIR2=$($MONTH$YEAR"_Blast_BC15")
echo $DIR1
echo $DIR2
This is the output I want for echo $DIR1 ... (12 Replies)
Discussion started by: anaigini45
12 Replies
LEARN ABOUT PHP
datetime.setisodate
DATETIME.SETISODATE(3) 1 DATETIME.SETISODATE(3)DateTime::setISODate - Sets the ISO date
Object oriented style
SYNOPSIS
public DateTime DateTime::setISODate (int $year, int $week, [int $day = 1])
DESCRIPTION
Procedural style
DateTime date_isodate_set (DateTime $object, int $year, int $week, [int $day = 1])
Set a date according to the ISO 8601 standard - using weeks and day offsets rather than specific dates.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $week
- Week of the date.
o $day
- Offset from the first day of the week.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setISODate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setISODate(2008, 2);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 2, 7);
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create();
date_isodate_set($date, 2008, 2);
echo date_format($date, 'Y-m-d') . "
";
date_isodate_set($date, 2008, 2, 7);
echo date_format($date, 'Y-m-d') . "
";
?>
The above examples will output:
2008-01-07
2008-01-13
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setISODate(2008, 2, 7);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 2, 8);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 53, 7);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2008-01-13
2008-01-14
2009-01-04
Example #3
Finding the month a week is in
<?php
$date = new DateTime();
$date->setISODate(2008, 14);
echo $date->format('n');
?>
The above examples will output:
3
SEE ALSO DateTime.setDate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETISODATE(3)