guys,
my requirment goes like this:
I have a file, and wish to filter out records where
1. The first letter is o or O
and
2. The next 4 following letter should not be ther
I do not wish to use pipe and wish to do it in one shot.
The best expression I came up with is:
grep ^*... (10 Replies)
When i do ls -ld RT_BP* i am getting the following list.
drwxrwx--- 2 user group 256 Oct 17 10:09 RT_BP809
drwxrwx--- 2user group 256 Oct 17 10:09 RT_BP809.O
drwxrwx--- 2 user group 256 Oct 17 10:09 RT_BP810
drwxrwx--- 2user group 256 Oct... (2 Replies)
Hi, guys. I have one question, hope somebody can give me a hand
I have a file called passwd, the contents of it arebelow:
***********************
...
goldsimj:x:5008:200:
goldsij2:x:5009:200:
whitej:x:5010:201:
brownj:x:5011:202:
goldsij3:x:5012:204:
greyp:x:5013:203:
...... (6 Replies)
Hi,
I am executing a svnlook command to check to see if the following line exists. I need a regular expression to represent the line.
A /test/test1/qa/test2/index.html
A /test/test1/qa/test3/test.jpg
A /test/test1/qa/test3/test1.jpg
A /test/test1/qa/test4/test.swf
I just need to extract... (9 Replies)
Hello,
How to print the field separator in awk? please see the following code:
cat a.txt
a 1s 2s 3s 4s
b 2s 4s
$ awk 'BEGIN{FS==" "} {print $2 $3 }' te
1s2s
2s4s
I want to get the following output :
1s 2s
2s 4s
How to realize this ?
$ cat te
a 1s,,2s 3s ... (11 Replies)
Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
Hi ,
I have few lines like
A20120101.ANU.ZIP
A20120401.ABC.ZIP
A20120105.KJK.ZIP
A20120809.JUG.ZIP
A20120101.MAT.ZIP
B20120301.ANU.XIP
I want to filter by
1. Files starting with A and Ending With Z ( ^A.*.ZIP$)
2. And either ANU, or KJK or MAT in the file name.
Hope my... (6 Replies)
Hello,
one step in a shell script i am writing, involves Grep command to search a regular expression in a line an only print the string after the match
an example line is below
/logs/GRAS/LGT/applogs/lgt-2016-08-24/2016-08-24.8.log.zip:2016-08-24 19:12:48,602 ERROR... (9 Replies)
I want to track only below:
I am using below, but it doesn't work: (6 Replies)
Discussion started by: proactiveaditya
6 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)