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Full Discussion: Regular expression in grep -E | awk print
Top Forums Shell Programming and Scripting Regular expression in grep -E | awk print Post 302358161 by EAGL€ on Thursday 1st of October 2009 12:51:57 PM
Old 10-01-2009
Quote:
Originally Posted by terry2009
Thanks, but would this work (this is a snippet of a much much larger script):

Code:
grep -E "[A-Z][0-9]" file.txt | sed 's#.*>\([A-Z][0-9]\).*#1,,,1,\1#' > out.txt

Hello friends, could you please tell me what does " > " stands for in SED part of the script? I understand all the regex except it,

regards
 

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LEARN ABOUT PLAN9

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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