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Top Forums Shell Programming and Scripting How to get the exit code of -exec in the find command Post 302357268 by oku on Tuesday 29th of September 2009 10:06:32 AM
Old 09-29-2009
Quote:
Originally Posted by agn
Instead of using -exec, try using &&.

Code:
$ find . -cmin -100 -type f && rsync -a --delete directory1/ directory2/


Ok I have tried that but how do I get the exit status back? I tried it with $? $! and the PIPESTAUS

Code:
find -type f -cmin 100 && cat /var/log/messages|wc -l

PS: I took the cat command on the messages file because that should give me for sure the exitstatus 1 back.

---------- Post updated at 04:06 PM ---------- Previous update was at 02:45 PM ----------

Thank you again for all your help!

I think I'm going to use the version pludi has posted. So far it is just modified on my test environment but hopefully I'm able to test it tomorrow on a real system (with bit more than 10 files and other userrights).

My solution (based on pludi's idea)
Code:
find . -type f -cmin 100 \( -exec rsync -a --delete {}/ directory2/{} \; -o -exec echo {} > failed.log \; \)

The good thing about that solution is, that I have the failed files written in a log.
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)

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