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Full Discussion: argument count
Top Forums Shell Programming and Scripting argument count Post 302347356 by KenJackson on Tuesday 25th of August 2009 12:38:38 PM
Old 08-25-2009
Quote:
Originally Posted by javajynx
lol well my next question was how do I determine input is digits or not?
I tried the if echo $1 | grep -qv '[^0-9-]'
but it doesn't appear to accept it as false if I enter a name ie enter 12345678 and it does the number part enter bob and it says invalid number.
Try this from the command line:
Code:
echo 1234 | grep -qv '[^0-9-]'  &&  echo RIGHT
echo 12A34 | grep -qv '[^0-9-]'  &&  echo WRONG

Quote:
Originally Posted by javajynx
Also after I get that figured out how do I get the line from the document that contains the name or number ie entered "bob jones" and it was found in the document. It needs to echo that result
ie Bob Jones 12345567
is there a grep option that returns the line itself?
What's the format of your file? Maybe something as simple as this:
Code:
grep "$NAME" file.txt

 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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