Hi
i want to print the time of a process in hours only..(or) in minutes only.Is there anyway to print the process such like that
when i give the commnand like following
#ps -eo pid,time
PID TIME
412 01:49:32
481 00:03
it shows in HH:MM:SS format:
Could anyone... (1 Reply)
i have the time 20100421043335 in format (date +%Y%m%d%H%M%S),and i want to be able to get the previous time 2 minutes ago,which is
20100421043135 (9 Replies)
I have several logs with where the time stamp in the logs are "YYYYMMDDHHMM".
I would like to check the last line in each file to make sure the entry is less than 5 minutes old.
My timezone is EST5EDT so the following will work for 1 hour. But I need something easy for 5 minutes ago.... (5 Replies)
In Redhat it is easy....
date --date="60 minutes ago"
How do you do this in Solaris?
I got creative and got the epoch time but had problems..
EPOCHTIME=`truss date 2>&1 | grep "time()" | awk '{print $3 - 900}'`
echo $EPOCHTIME
TIME=`perl -e 'print scalar(localtime("$EPOCHTIME")),... (5 Replies)
Hello All
I know the general Logic behind it but do not know the shell programming so much.
For Example, The Time is stored in a given Variable
if the Time is 0800 then i need to extract the last digits of the number and Add it to the Remaining Digit of the Number which is multiplied by... (7 Replies)
Hi Folks,
I have a text file that has only time in the format HH:MM:SS like seen below.
21:36:17
23:52:08
I need to find the difference in minutes alone from this text file so the result would be 136.
Thanks
Jay (11 Replies)
Hello,
date --date '-60 min ago' +'%Y-%m-%d %H:%M:%S,%3N'
Above command gives the date and time minus 60 minutes
but the problem i am facing is, i do not want to hardcode the value 60
it is stored in a variable var=60
now if i run below command , i get error
date --date '-$var min... (3 Replies)
Hello all,
Info:
System RedHat 7.5
I need to create a script that based on the creation time,
if the file is older then 5 minutes then execute some stuff, if not exit.
I thought to get the creation time and minutes like this.
CreationTime=$(stat -c %y /tmp/test.log | awk -F" " '{ print... (3 Replies)
A process xyz is running and creating file1, file2, file3, .... filen. how do i know if the process has stopped and createtime of the last file (filen) is older than 5 minutes?
OS is AIX (3 Replies)
Discussion started by: malaika
3 Replies
LEARN ABOUT DEBIAN
io::async::timer::absolute
IO::Async::Timer::Absolute(3pm) User Contributed Perl Documentation IO::Async::Timer::Absolute(3pm)NAME
"IO::Async::Timer::Absolute" - event callback at a fixed future time
SYNOPSIS
use IO::Async::Timer::Absolute;
use POSIX qw( mktime );
use IO::Async::Loop;
my $loop = IO::Async::Loop->new;
my @time = gmtime;
my $timer = IO::Async::Timer::Absolute->new(
time => mktime( 0, 0, 0, $time[4]+1, $time[5], $time[6] ),
on_expire => sub {
print "It's midnight
";
$loop->stop;
},
);
$loop->add( $timer );
$loop->run;
DESCRIPTION
This subclass of IO::Async::Timer implements one-shot events at a fixed time in the future. The object waits for a given timestamp, and
invokes its callback at that point in the future.
For a "Timer" object that waits for a delay relative to the time it is started, see instead IO::Async::Timer::Countdown.
EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters:
on_expire
Invoked when the timer expires.
PARAMETERS
The following named parameters may be passed to "new" or "configure":
on_expire => CODE
CODE reference for the "on_expire" event.
time => NUM
The epoch time at which the timer will expire.
Once constructed, the timer object will need to be added to the "Loop" before it will work.
Unlike other timers, it does not make sense to "start" this object, because its expiry time is absolute, and not relative to the time it is
started.
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2012-10-24 IO::Async::Timer::Absolute(3pm)