07-24-2009
Thanks Igor
Great help!
That worked just fine but right now I've another problem, cuz my files for some lines the 3d element is a NaN (Not a Number) and I cant do the estatistic work using the increment without a routine that removes that elementes from my calculation
Have any more Ideas?
Thak you for your time!
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1|B|22,59
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2|A|63,71
2|C|23,92
5|B|19,49
5|C|67,58
expecting something like that
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LEARN ABOUT MOJAVE
ctanhl
CTANH(3) BSD Library Functions Manual CTANH(3)
NAME
ctanh -- complex hyperbolic tangent function
SYNOPSIS
double complex
ctanh(double complex z);
long double complex
ctanhl(long double complex z);
float complex
ctanhf(float complex z);
DESCRIPTION
ctanh(z) computes the hyperbolic tangent of the complex floating-point number z.
For all complex floating point numbers z,
ctanh(conj(z)) = conj(ctanh(z)),
ctanh(-z) = -ctanh(z).
SPECIAL VALUES
The symmetries of ctanh() are used to abbreviate the specification of special values.
ctanh(0 + 0i) returns 0 + 0i.
ctanh(0 + inf i) returns NaN + NaN i, and raises the invalid flag.
ctanh(0 + NaN i) returns NaN + NaN i.
ctanh(x + inf i) returns NaN + NaN i, and raises the invalid flag, for finite nonzero x.
ctanh(x + NaN i) returns NaN + NaN i, for finite nonzero x.
ctanh(inf + 0i) returns 1 + 0i.
ctanh(inf + yi) returns 1 +- 0i, for finite positive y, with the sign chosen to match the sign of sin(2y).
ctanh(inf + inf i) returns 1 + 0i.
ctanh(inf + NaN i) returns 1 + 0i.
ctanh(NaN + 0i) returns NaN + 0i.
ctanh(NaN + yi) returns NaN + NaN i, for nonzero numbers y.
ctanh(NaN + NaN i) returns NaN + NaN i.
NOTES
SEE ALSO
ctan(3) complex(3)
STANDARDS
The ctanh() function conforms to ISO/IEC 9899:2011.
4th Berkeley Distribution December 11, 2006 4th Berkeley Distribution