07-24-2009
Ho can i grep for yestdarday's data in unix
I have the date field in my log file in the format shown below..
(07/23/2009 03:54:02.107)aaaaaa bbbbbb
I want to grep for month/date(7/23) field of yestdarday's data.
found the below command in this forum which is not working in my SUN Solaris box.
date -d "yesterday" +"%d %b %Y"
Please suggest me any other alternatives...
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sulog(4) File Formats sulog(4)
NAME
sulog - su command log file
SYNOPSIS
/var/adm/sulog
DESCRIPTION
The sulog file is a record of all attempts by users on the system to execute the su(1M) command. Each time su(1M) is executed, an entry
is added to the sulog file.
Each entry in the sulog file is a single line of the form:
SU date time
result port user-newuser
where
date The month and date su(1M) was executed. date is displayed in the form mm/dd where mm is the month number and dd is the
day number in the month.
time The time su(1M) was executed. time is displayed in the form HH/MM where HH is the hour number (24 hour system) and MM
is the minute number.
result The result of the su(1M) command. A ` + ' sign is displayed in this field if the su attempt was successful; otherwise a
` - ' sign is displayed.
port The name of the terminal device from which su(1M) was executed.
user The user id of the user executing the su(1M) command.
newuser The user id being switched to with su(1M).
EXAMPLES
Example 1: A sample sulog file.
Here is a sample sulog file:
SU 02/25 09:29 + console root-sys
SU 02/25 09:32 + pts/3 user1-root
SU 03/02 08:03 + pts/5 user1-root
SU 03/03 08:19 + pts/5 user1-root
SU 03/09 14:24 - pts/5 guest3-root
SU 03/09 14:24 - pts/5 guest3-root
SU 03/14 08:31 + pts/4 user1-root
FILES
/var/adm/sulog su log file
/etc/default/su contains the default location of sulog
SEE ALSO
su(1M)
SunOS 5.10 6 Jun 1994 sulog(4)