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Full Discussion: Using variables created sequentially in a loop while still inside of the loop [bash]
Top Forums Shell Programming and Scripting Using variables created sequentially in a loop while still inside of the loop [bash] Post 302328195 by DeCoTwc on Tuesday 23rd of June 2009 04:59:10 PM
Old 06-23-2009
Quote:
Originally Posted by rakeshawasthi
can you put set -x in the second line of your file "question" and paste the output here...
This is the output with set -x command added:

Code:
(16:48:46\[deco@S.Man)
[~/bin]$ ./question 
++ listQpsk 40
++ grep -w '[1-4]'
+ tab=' 40 SMANHUBAQPSK1          1    1342      1194        88
 40 SMANHUBAQPSK1          2    1668      1464        87
 40 SMANHUBAQPSK1          3    1883      1535        81
 40 SMANHUBAQPSK1          4    1685      1399        83'
+ seq=1
+ num=4
+ [[ 1 -gt 4 ]]
++ echo ' 40 SMANHUBAQPSK1          1    1342      1194        88
 40 SMANHUBAQPSK1          2    1668      1464        87
 40 SMANHUBAQPSK1          3    1883      1535        81
 40 SMANHUBAQPSK1          4    1685      1399        83'
++ grep -w 1
++ awk '{print $5}'
+ eval count1=1194
++ count1=1194
+ seq=2
+ [[ 2 -gt 4 ]]
++ echo ' 40 SMANHUBAQPSK1          1    1342      1194        88
 40 SMANHUBAQPSK1          2    1668      1464        87
 40 SMANHUBAQPSK1          3    1883      1535        81
 40 SMANHUBAQPSK1          4    1685      1399        83'
++ grep -w 2
++ awk '{print $5}'
+ eval count2=1464
++ count2=1464
+ seq=3
+ [[ 3 -gt 4 ]]
++ echo ' 40 SMANHUBAQPSK1          1    1342      1194        88
 40 SMANHUBAQPSK1          2    1668      1464        87
 40 SMANHUBAQPSK1          3    1883      1535        81
 40 SMANHUBAQPSK1          4    1685      1399        83'
++ grep -w 3
++ awk '{print $5}'
+ eval count3=1535
++ count3=1535
+ seq=4
+ [[ 4 -gt 4 ]]
++ echo ' 40 SMANHUBAQPSK1          1    1342      1194        88
 40 SMANHUBAQPSK1          2    1668      1464        87
 40 SMANHUBAQPSK1          3    1883      1535        81
 40 SMANHUBAQPSK1          4    1685      1399        83'
++ grep -w 4
++ awk '{print $5}'
+ eval count4=1399
++ count4=1399
+ seq=5
+ [[ 5 -gt 4 ]]
+ echo 1194
1194
+ echo 1464
1464
+ echo 1535
1535
+ echo 1399
1399

However I was able to find a working solution to my problem:

Code:
(16:48:50\[deco@S.Man)
[~/bin]$ cat orig.question 
#!/usr/bin/bash
tab=`listQpsk 40|grep -w [1-4]`
seq=1
num=4
until [[ $seq -gt $num ]];do
var="count$seq"
eval var=`echo "$tab"|grep -w $seq|awk '{print $5}'`
echo $var
seq=$(($seq+1))
done

(16:50:12\[deco@S.Man)
[~/bin]$ ./orig.question 
1194
1464
1534
1399

 

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LEARN ABOUT CENTOS

seq

SEQ(1)								   User Commands							    SEQ(1)

NAME

       seq - print a sequence of numbers

SYNOPSIS

       seq [OPTION]... LAST
       seq [OPTION]... FIRST LAST
       seq [OPTION]... FIRST INCREMENT LAST

DESCRIPTION

       Print numbers from FIRST to LAST, in steps of INCREMENT.

       Mandatory arguments to long options are mandatory for short options too.

       -f, --format=FORMAT
	      use printf style floating-point FORMAT

       -s, --separator=STRING
	      use STRING to separate numbers (default: 
)

       -w, --equal-width
	      equalize width by padding with leading zeroes

       --help display this help and exit

       --version
	      output version information and exit

       If FIRST or INCREMENT is omitted, it defaults to 1.  That is, an omitted INCREMENT defaults to 1 even when LAST is smaller than FIRST.  The
       sequence of numbers ends when the sum of the current number and INCREMENT would become greater than LAST.  FIRST, INCREMENT, and  LAST  are
       interpreted  as	floating  point values.  INCREMENT is usually positive if FIRST is smaller than LAST, and INCREMENT is usually negative if
       FIRST is greater than LAST.  FORMAT must be suitable for printing one argument of type 'double'; it defaults to %.PRECf	if  FIRST,  INCRE-
       MENT, and LAST are all fixed point decimal numbers with maximum precision PREC, and to %g otherwise.

       GNU coreutils online help: <http://www.gnu.org/software/coreutils/> Report seq translation bugs to <http://translationproject.org/team/>

AUTHOR

       Written by Ulrich Drepper.

COPYRIGHT

       Copyright (C) 2013 Free Software Foundation, Inc.  License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>.
       This is free software: you are free to change and redistribute it.  There is NO WARRANTY, to the extent permitted by law.

SEE ALSO

       The  full  documentation  for seq is maintained as a Texinfo manual.  If the info and seq programs are properly installed at your site, the
       command

	      info coreutils 'seq invocation'

       should give you access to the complete manual.

GNU coreutils 8.22						     June 2014								    SEQ(1)
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