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Top Forums Shell Programming and Scripting incremental addition of hex decimal number in one field Post 302321658 by durden_tyler on Monday 1st of June 2009 10:26:33 PM
Old 06-01-2009
Quote:
Originally Posted by diddi_linux
my requirement is simple i want to deptno field to get incremental hex value..i am doing manually by entering 0 1 2 3 for each field in the file..i want it one shot...
Here's one way to do it:

Code:
$
$ perl -e 'foreach $i (0..30){printf "dept%d = %x\n",$i,$i}'
dept0 = 0
dept1 = 1
dept2 = 2
dept3 = 3
dept4 = 4
dept5 = 5
dept6 = 6
dept7 = 7
dept8 = 8
dept9 = 9
dept10 = a
dept11 = b
dept12 = c
dept13 = d
dept14 = e
dept15 = f
dept16 = 10
dept17 = 11
dept18 = 12
dept19 = 13
dept20 = 14
dept21 = 15
dept22 = 16
dept23 = 17
dept24 = 18
dept25 = 19
dept26 = 1a
dept27 = 1b
dept28 = 1c
dept29 = 1d
dept30 = 1e
$

tyler_durden
 

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