05-19-2009
Displaying lines of a file where the second field matches a pattern
Howdy.
I know this is most likely possible using sed or awk or grep, most likely a combination of them together, but how would one go about running a grep like command on a file where you only try to match your pattern to the second field in a line, space delimited?
Example:
You are searching for xxx in each line of a file where the file is laid out as
aaa bbb ccc ddd eee
aaa bbb ccc ddd eee
Each one of those three letter groupings being any number of things. I only want to display the lines of the files where bbb = xxx.
Possible?
Thanks if anyone knows.
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)