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Top Forums Shell Programming and Scripting error "awk: (FILENAME=- FNR=23) fatal: division by zero attempted" Post 302314866 by justbow on Sunday 10th of May 2009 11:21:50 PM
Old 05-11-2009
yap thanks.. but we should print $1
so we missing $1 in line 23 and 24 ??

Quote:
16 ,100 ,
27 ,100 ,
26 ,100 ,
44 ,100 ,
28 ,100 ,
23 ,100 ,
187 ,100 ,
14 ,93.3333 ,
98 ,98.9899 ,
41 ,100 ,
47 ,100 ,
61 ,100 ,
78 ,97.5 ,
40 ,100 ,
105 ,99.0566 ,
175 ,99.4318 ,
175 ,100 ,
67 ,100 ,
118 ,100 ,
30 ,100 ,
149 ,99.3333 ,
210 ,99.5261 ,
------>> line 23 and 24
112 ,100 ,
can we print blank line for this case ?
 

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IMAGICK.GETITERATORINDEX(3)						 1					       IMAGICK.GETITERATORINDEX(3)

Imagick::getIteratorIndex - Gets the index of the current active image

SYNOPSIS
int Imagick::getIteratorIndex (void ) DESCRIPTION
Returns the index of the current active image within the Imagick object. This method is available if Imagick has been compiled against ImageMagick version 6.2.9 or newer. RETURN VALUES
Returns an integer containing the index of the image in the stack. ERRORS
/EXCEPTIONS Throws ImagickException on error. EXAMPLES
Example #1 Using Imagick.getIteratorIndex(3): Create images, set and get the iterator index <?php $im = new Imagick(); $im->newImage(100, 100, new ImagickPixel("red")); $im->newImage(100, 100, new ImagickPixel("green")); $im->newImage(100, 100, new ImagickPixel("blue")); $im->setIteratorIndex(1); echo $im->getIteratorIndex(); ?> SEE ALSO
Imagick.setIteratorIndex(3), Imagick.getImageIndex(3), Imagick.setImageIndex(3). PHP Documentation Group IMAGICK.GETITERATORINDEX(3)
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