grep on '-141-' should be sufficient. The backslash or the double minus sign prevents grep to treat the regexp as an option, but not all versions of grep support them both:
I have following content in the file
CancelPolicyMultiLingual3=U|PC3|EN
RestaurantInfoCode1=U|restID1|1
.....
I am trying to use following matching extression
\|(+)
to get this
PC3|EN
restID1|1
Obviously it does not work.
Any ideas? (13 Replies)
Hi Gurus,
I need help with regular expressions. I want to create a regular expression which will take only alpha-numeric characters for 7 characters long and will throw out an error if longer than that.
i tried various combinations but couldn't get it, please help me how to get it guys.
... (2 Replies)
Hello,
Let say I have a string with content "Free 100%". How can extract only "100" using ksh? I would this machanism to work if instead of "100" there is any kind of combination of numbers(ex. "32", "1238", "1"). I want to get only the digits.
I have written something like this:
... (4 Replies)
Hi,
below is a piece of code written by my predecessor at work.
I'm kind of a newbie and am trying to figure out all the regular expressions in this piece of code.
It is really a tough time for me to figure out all the regular expressions.
Please shed some light on the regular expressions... (3 Replies)
In regular expressions with grep(or egrep), ^ works if we want something in starting of line..but what if we write ^^^ or ^ for pattern matching??..Hope u all r familiar with regular expressions for pattern matching.. (1 Reply)
#!/usr/bin/perl
$word = "one last challenge";
if ( $word =~ /^(\w+).*\s(\w+)$/ )
{
print "$1";
print "\n";
print "$2";
}
The output shows that "$1" is with result one and "$2" is with result challenge. I am confused about how this pattern match expression works step by step. I... (8 Replies)
I have a file that I'm trying to find all the cases of phone number extensions and deleting them. So input file looks like:
abc
x93825
def
13234
x52673
hello
output looks like:
abc
def
13234
hello
Basically delete lines that have 5 numbers following "x". I tried: x\(4) but it... (7 Replies)
I am new to shell scripts.Can u please help me on this req.
test_user = "Arun"
if
echo "test_user is a word"
else
echo "test_user is not a word" (1 Reply)
I need to pick a part of string lets stay started with specific character and end with specific character to replace using sed command
the line is like this:my audio book 71-skhdfon1dufgjhgf8.wav'
I want to move the characters beginning with - end before.
I have different files with random... (2 Replies)
Discussion started by: XP_2600
2 Replies
LEARN ABOUT MOJAVE
islower
ISLOWER(3) BSD Library Functions Manual ISLOWER(3)NAME
islower -- lower-case character test
LIBRARY
Standard C Library (libc, -lc)
SYNOPSIS
#include <ctype.h>
int
islower(int c);
DESCRIPTION
The islower() function tests for any lower-case letters. The value of the argument must be representable as an unsigned char or the value of
EOF.
In the ASCII character set, this includes the following characters (with their numeric values shown in octal):
141 ``a'' 142 ``b'' 143 ``c'' 144 ``d'' 145 ``e''
146 ``f'' 147 ``g'' 150 ``h'' 151 ``i'' 152 ``j''
153 ``k'' 154 ``l'' 155 ``m'' 156 ``n'' 157 ``o''
160 ``p'' 161 ``q'' 162 ``r'' 163 ``s'' 164 ``t''
165 ``u'' 166 ``v'' 167 ``w'' 170 ``x'' 171 ``y''
172 ``z''
RETURN VALUES
The islower() function returns zero if the character tests false and returns non-zero if the character tests true.
COMPATIBILITY
The 4.4BSD extension of accepting arguments outside of the range of the unsigned char type in locales with large character sets is considered
obsolete and may not be supported in future releases. The iswlower() function should be used instead.
SEE ALSO ctype(3), isalnum_l(3), iswlower(3), tolower(3), ascii(7)STANDARDS
The islower() function conforms to ISO/IEC 9899:1990 (``ISO C90'').
BSD July 17, 2005 BSD