Hi,
Is it possible to create a dynamic array in shell script. I am trying to get the list of logfiles that created that day and put it in a dynamic array. I am not sure about it. help me
New to scripting
Gundu (3 Replies)
My requirement is to create a KSH to generate the SQL select statement in oracle with all the columns and optional where condition if given the table name as input to the program
Have any of you worked with a similar requirement? Can you give me some inputs?
Regards,
Kousikan (2 Replies)
dear pro-coders,
is there any command out there that takes out the front spaces from a string?
sample strings:
4 members
5 members
3 members
but it has to be like so:
4 members
5 members
3 members (3 Replies)
Hi everyon,
I am trying to search for a pattern in a file and add "//" to the begining of the file.
lets say i want to comment out a line from my codes. the line that should be commented out contains the word "reset". i need to search for the word "reset" and comment out that specific line. is... (5 Replies)
Hi,
Can anybody help me how to add a word in front of a line in a file.Actually it is bit tricky to add a word. i will give a sample for this:
Input :
1110001 ABC DEF
1110001 EFG HIJ
1110001 KLM NOP
1110002 QRS RST
1110002 UVW XYZ
Output:
%HD% 1110001 ABC DEF
%DT% 1110001 EFG HIJ... (4 Replies)
Hello,
Did any one know how to use perl join line and add | in front
Input-->
timestamp=2009-11-10-04.55.20.829347;
a;
b;
c;
ddaa;
timestamp=2009-11-10-04.55.20.829347;
aa;
bb;
cc;
Output-->
... (2 Replies)
Hi
I've one file full of paths of certain files and I want to add some extra file words in front of all the paths. for eg:
i have a file name test.txt which show some details only..
024_hd/044/0344eng.txt
035_bv/222/editor.jpg
here I want to add /usr/people/indiana/ infront of all the... (4 Replies)
I'm trying to convert this line:
to
\ with sed.
This is what I have so far:
sed -e 's/\]*\)\]/\\\\\/'
but this still gives me .
Any suggestions? (15 Replies)
Discussion started by: lehaste
15 Replies
LEARN ABOUT OSX
perlio::via::dynamic
dynamic(3) User Contributed Perl Documentation dynamic(3)NAME
PerlIO::via::dynamic - dynamic PerlIO layers
SYNOPSIS
open $fh, $fname;
$p = PerlIO::via::dynamic->new
(translate =>
sub { $_[1] =~ s/$Filename[:ws-./\]*$/$Filename: $fname$/e},
untranslate =>
sub { $_[1] =~ s/$Filename[:ws-./\]*$/$Filename$/});
$p->via ($fh);
binmode $fh, $p->via; # deprecated
DESCRIPTION
"PerlIO::via::dynamic" is used for creating dynamic PerlIO layers. It is useful when the behavior or the layer depends on variables. You
should not use this module as via layer directly (ie :via(dynamic)).
Use the constructor to create new layers, with two arguments: translate and untranslate. Then use "$p-"via ($fh)> to wrap the handle. Once
<$fh> is destroyed, the temporary namespace for the IO layer will be removed.
Note that PerlIO::via::dynamic uses the scalar fields to reference to the object representing the dynamic namespace.
OPTIONS
translate
A function that translate buffer upon write.
untranslate
A function that translate buffer upon read.
use_read
Use "READ" instead of "FILL" for the layer. Useful when caller expect exact amount of data from read, and the "untranslate" function
might return different length.
By default "PerlIO::via::dynamic" creates line-based layer to make "translate" implementation easier.
AUTHORS
Chia-liang Kao <clkao@clkao.org>
COPYRIGHT
Copyright 2004 by Chia-liang Kao <clkao@clkao.org>.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
See <http://www.perl.com/perl/misc/Artistic.html>
perl v5.16.2 2008-05-31 dynamic(3)