Now i did manually by changing each code of line one by one.. Could you please check it now..
Hi,
Some part of output:
================
$ hwmgr show scsi
SCSI DEVICE DEVICE DRIVER NUM DEVICE FIRST
HWID: DEVICEID HOSTNAME TYPE SUBTYPE OWNER PATH FILE VALID PATH
-------------------------------------------------------------------------
68: 0 mullins disk none 0 1 dsk0 [0/0/0]
69: 1 mullins disk none 0 1 dsk1 [0/1/0]
71: 4 mullins disk none 0 4 scp0 [2/0/0]
72: 5 mullins disk none 2 4 dsk2 [2/0/3]
73: 6 mullins disk none 2 4 dsk3 [2/0/4]
74: 7 mullins disk none 2 4 dsk4 [2/0/6]
75: 8 mullins disk none 2 4 dsk5 [2/0/7]
76: 9 mullins disk none 2 4 dsk6 [2/0/8]
77: 10 mullins disk none 0 4 dsk7 [2/0/9]
78: 11 mullins disk none 0 4 dsk8 [2/0/10]
79: 12 mullins disk none 0 4 dsk9 [2/0/11]
80: 13 mullins disk none 0 4 dsk10 [2/0/12]
================================================================
Main intention of doing this is to meet BID value=35 by using required number of disks.
a[x]=x (unknown value to programmer)varies from machine to machine.
And a[x] value can be found from below code ..
hwmgr show scsi > scsi.tmp
while read line; do
a[x]=`echo $line | grep "dsk" | awk '{ print $7 }'`
Coming to BID concept:
--------------------------------
BID value =(No of partitions * NUM PATH value).
In general each disk has 4 partitions (a,b,g,h) and and for each partition(a,b,g,h) their wll be NUM PATH value.Each partition NUM PATH value will be equal to NUM PATH value of that particular disk.
Example:- Suppose dsk1 has NUM PATH=4 then partition "a" has Total number of paths=4 partition "b" total number of paths=4 Partition "g" total number of paths=4 partition "h" total number of paths=4 Hence,if you use dsk1 then we can have BID value=(No of partitions * NUM PATH)=4*4=16.
So our requirement is to meet BID value=35.
After getting NUM PATH value by above code,we must use the required number of disks to meet BID=35.
Example:Let say dsk2 and dsk3 has NUMPATH=4 then we can get BID value=16+16=32) Still we didnt meet BID=35 and here we must note that we can't use the disk which has NUM PATH=4 now at this stage because 32+4=36 (not equal to 35) so we must use less than NUM PATH=4 , say if you find NUM PATH=1(less than NUM PATH=4)so we can proceede and here we must check how many partitions to be used to meet BID value=35.In this case only 3 partitions are required which has NUM PATH=1 so finally
32+3=35..
========================================================
I wrote the below code as per my above information..
Could you check it and correct me if you have better idea..
Request you to please provide inputs for this...
I have input file like this
Input file:
ABC|abc_etc_passwd
XYZ|XYZ_etc_passwd
zXY|XYZ_etc_passwd
IJK|test_etc_passwd
KLM|test_etc_passwd
i want to do following in a loop.
grep 'ABC' *abc_etc_passwd*
grep 'XYZ' *XYZ_etc_passwd*
grep 'ZXY' *ZXY_etc_passwd*
i have tried this
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