I have the following text format in a file which lists the question first and then 5 choices
after that the explanantion and finally the answer.
1.The amount of time it takes for most of a worker’s occupational knowledge and skills to become
obsolete has been declining because of the... (2 Replies)
Hi Experts,
Help needed on joining one line above & below to the pattern matched string line.
The input file, required output is mentioned below
Input file
ABCD DEFG5 42.0.1-63.38.31
KKKK iokl IP Connection Available
ABCD DEFG5 42.0.1-63.38.31
... (7 Replies)
Can somebody help me with this? I'm sure it's a no-brainer if you know awk... but I don't.
Input:
Blah
Blah
Me love you
long time
Blah
Blah
awk magic with 'long time'
==>
Output:
Blah
Blah
Me love you long time (0 Replies)
Hello every,
I am stuck in a problem. I have file like this. I want to add the fifth field of the match pattern line above the lines starting with "# @D". The delimiter is "|"
eg
>
# @D0.00016870300|0.05501020000|12876|12934|3||Qp||Pleistocene||"3 Qp Pleistocene"|Q
# @P... (5 Replies)
Hi,
I have two files file1.txt and file2.txt. Please see the attachments.
In file2.txt (which actually is a diff output between two versions of file1.txt.), I extract the pattern corresponding to 1172c1172. Now ,In file1.txt I have to search for this pattern 1172c1172 and if found, I have to... (9 Replies)
Hello.
I want to find a line that has "new = 0" in it, then search back based on field $4 () in the current line, and find the first line that has field $4 and "last fetch"
Grep or Awk preferred.
Here is what the data looks like:
2013-12-12 12:10:30,117 TRACE last fetch: Thu Dec 12... (7 Replies)
Hi I want to print the line until pattern is matched.
I am using below code:
sed -n '1,/pattern / p' file
It is working fine for me , but its not working for exact match.
sed -n '1,/^LAC$/ p' file
Input:
LACC FEGHRA 0
LACC FACAF 0
LACC DARA 0
LACC TALAC 0
LAC ILACTC 0... (8 Replies)
Hello,
I have below format log file,
Comparing csv_converted_files/2201/9747.1012H67126.5077292103609547345.csv and csv_converted_files/22019/97447.1012H67126.5077292103609547345.csv
Comparing csv_converted_files/2559/9447.1012H67126.5077292103609547345.csv and... (6 Replies)
Hello,
I have a file which has the below contents :
VG_name LV_name LV_size in MB LV_option LV_mountpoint owner group y
testdg rahul2lv 10 "-A y -L" /home/abc2 ... (6 Replies)
How to grep for searching a string within a begin and end pattern of a file.
Sent from my Redmi 3S using Tapatalk (8 Replies)
Discussion started by: Baishali
8 Replies
LEARN ABOUT PLAN9
pam_authenticate
PAM_AUTHENTICATE(3) Linux-PAM Manual PAM_AUTHENTICATE(3)NAME
pam_authenticate - account authentication
SYNOPSIS
#include <security/pam_appl.h>
int pam_authenticate(pam_handle_t *pamh, int flags);
DESCRIPTION
The pam_authenticate function is used to authenticate the user. The user is required to provide an authentication token depending upon the
authentication service, usually this is a password, but could also be a finger print.
The PAM service module may request that the user enter their username vio the the conversation mechanism (see pam_start(3) and
pam_conv(3)). The name of the authenticated user will be present in the PAM item PAM_USER. This item may be recovered with a call to
pam_get_item(3).
The pamh argument is an authentication handle obtained by a prior call to pam_start(). The flags argument is the binary or of zero or more
of the following values:
PAM_SILENT
Do not emit any messages.
PAM_DISALLOW_NULL_AUTHTOK
The PAM module service should return PAM_AUTH_ERR if the user does not have a registered authentication token.
RETURN VALUES
PAM_ABORT
The application should exit immediately after calling pam_end(3) first.
PAM_AUTH_ERR
The user was not authenticated.
PAM_CRED_INSUFFICIENT
For some reason the application does not have sufficient credentials to authenticate the user.
PAM_AUTHINFO_UNVAIL
The modules were not able to access the authentication information. This might be due to a network or hardware failure etc.
PAM_MAXTRIES
One or more of the authentication modules has reached its limit of tries authenticating the user. Do not try again.
PAM_SUCCESS
The user was successfully authenticated.
PAM_USER_UNKNOWN
User unknown to authentication service.
SEE ALSO pam_start(3), pam_setcred(3), pam_chauthtok(3), pam_strerror(3), pam(7)Linux-PAM Manual 06/04/2011 PAM_AUTHENTICATE(3)