05-19-2008
Day of month and year to mmddyyyy
I have a date that looks like this:
2008/100:18:40:47.040
I need it to look like this:
2008 04 09 18 40 47 040
I have looked at datecalc and it doesn't seem like it takes the day of year for this year (or whatever year is input) and converts it into month and day. It also has to account for leap years. Did I not see it there? Is there some easy way to convert this? Thanks.
Allyson
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LEARN ABOUT PHP
cal_to_jd
CAL_TO_JD(3) 1 CAL_TO_JD(3)
cal_to_jd - Converts from a supported calendar to Julian Day Count
SYNOPSIS
int cal_to_jd (int $calendar, int $month, int $day, int $year)
DESCRIPTION
cal_to_jd(3) calculates the Julian day count for a date in the specified $calendar. Supported $calendars are CAL_GREGORIAN, CAL_JULIAN,
CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $calendar
- Calendar to convert from, one of CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH or CAL_FRENCH.
o $month
- The month as a number, the valid range depends on the $calendar
o $day
- The day as a number, the valid range depends on the $calendar
o $year
- The year as a number, the valid range depends on the $calendar
RETURN VALUES
A Julian Day number.
SEE ALSO
cal_from_jd(3), frenchtojd(3), gregoriantojd(3), jewishtojd(3), juliantojd(3), unixtojd(3).
PHP Documentation Group CAL_TO_JD(3)