Sponsored Content
Full Discussion: Compose variable name
Top Forums Shell Programming and Scripting Compose variable name Post 302192862 by potro on Thursday 8th of May 2008 04:05:46 AM
Old 05-08-2008
Originally Posted by Annihilannic
Use eval to force the lines to be evaluated twice, once to insert the $CRT value, and a second time to do the assignment or substitution.

eval echo "\$LISTEN_PORT$CRT"

Also $CRT++ is not valid shell syntax.
This is not working neither:
Please type the Listen Port and F when finish : (current value: 8081)
./listen.sh: line 32: 1+1=8082: command not found
Please type the Listen Port and F when finish : (current value: 8082)

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Sed variable substitution when variable constructed of a directory path

Hello, i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem. my var1 is a string constructed like this: filename1 filerev1 filepath1 my var2 is another string constructed like this: filename2 filerev2 filepath2 when i do... (2 Replies)
Discussion started by: alrinno
2 Replies

2. Shell Programming and Scripting

Insert a line including Variable & Carriage Return / sed command as Variable

I want to instert Category:XXXXX into the 2. line something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong: sed "2i\\${n}Category:$cat\n" Sample: Titel Blahh Blahh abllk sdhsd sjdhf Blahh Blah Blahh Blahh Should look like... (2 Replies)
Discussion started by: lowmaster
2 Replies

3. Shell Programming and Scripting

How to define a variable with variable definition is stored in a variable?

Hi all, I have a variable say var1 (output from somewhere, which I can't change)which store something like this: echo $var1 name=fred age=25 address="123 abc" password=pass1234 how can I make the variable $name, $age, $address and $password contain the info? I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies

4. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

5. Shell Programming and Scripting

Variable not found error for a variable which is returned from stored procedure

can anyone please help me with this: i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure... ... (4 Replies)
Discussion started by: swap21783
4 Replies

6. Red Hat

How to pass value of pwd as variable in SED to replace variable in a script file

Hi all, Hereby wish to have your advise for below: Main concept is I intend to get current directory of my script file. This script file will be copied to /etc/init.d. A string in this copy will be replaced with current directory value. Below is original script file: ... (6 Replies)
Discussion started by: cielle
6 Replies

7. Shell Programming and Scripting

awk: compose regex in variable and then use its contents like $0 ~ var

A question to the awk pundits: I was thinking about composing a regex in a variable and then use its contents like $0 ~ var instead of $0 ~ /r/. Sort of indirection. Did someone run into this? Is it possible at all? (3 Replies)
Discussion started by: RudiC
3 Replies

8. Shell Programming and Scripting

[Solved] How to increment and add variable length numbers to a variable in a loop?

Hi All, I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Discussion started by: danish0909
5 Replies

9. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
REMQUO(3)						   BSD Library Functions Manual 						 REMQUO(3)

remquo -- floating-point remainder and quotient function SYNOPSIS
#include <math.h> double remquo(double x, double y, int *quo); long double remquol(long double x, long double y, int *quo); float remquof(float x, float y, int *quo); DESCRIPTION
The remquo() functions compute the value r such that r = x - n*y, where n is the integer nearest the exact value of x/y. If there are two integers closest to x/y, n shall be the even one. If r is zero, it is given the same sign as x. This is the same value that is returned by the remainder() function. remquo() also calculates the lower seven bits of the integral quotient x/y, and gives that value the same sign as x/y. It stores this signed value in the object pointed to by quo. SPECIAL VALUES
remquo(x, y, quo) returns a NaN and raises the "invalid" floating-point exception if x is infinite or y is 0. VECTOR OPERATIONS
If you need to apply the remquo() function to SIMD vectors or arrays, using the following functions provided by the Accelerate.framework may give significantly better performance: #include <Accelerate/Accelerate.h> vFloat vremquo(vFloat x, vFloat y, vUInt32 *q); SEE ALSO
math(3), remainder(3) STANDARDS
The remquo() functions conform to ISO/IEC 9899:2011. BSD
December 11, 2006 BSD

Featured Tech Videos

All times are GMT -4. The time now is 01:27 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy