I have no idea why I can't get this to work, if anybody can help i would appreciate it.
#!/bin/bash
x=`cat counter.txt | wc -l`
y= '$x / 7'
printf "%d People have visited this page" $y
:confused: (2 Replies)
I am using egrep to extract numbers from a file and storing them as variables in a script. But I am not able to do any arithmetic operations on the variables using "expr" because it stores them as char and not integers. Here is my code and the error I get. Any help will be appreciated.
#!/bin/sh... (3 Replies)
Hi all,
I would appreciate if anyone knows how to perform adding to date.
As for normal date, i can easily plus with any number.
But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul.
Thanks in advance for your help. (4 Replies)
Hi
I have a file with 3 columns. say,
infile:
1 50 68
34 3 23
23 4 56
-------
-------
I want to generate n files from this file using a loop so that 1st column in output file is (column1 of infile/(2*n+2.561))
I am doing like this:
for ((i=1; i<=3; i++))
do
a=`echo... (3 Replies)
I am writing a script in zsh shell, it fetchs a number from a file using the awk command, store it as a variable, which in my case is a small number 0.62000. I want to change this number by multiplying it by 1000 to become 620.0 using the command in the script
var2=$((var1*1000))
trouble is... (2 Replies)
input:
Name|Operation
rec_10|1+2+2-
Output:
rec_10|1
Basically I am trying to calculate the result of "the path" in $3 where the operators follow the number and not preceding them like we normally do:
rec_10: +1+2-2=1
But I realise (I am sure there is a good reason for that) that awk... (7 Replies)
Hi,
Here is the script i try to perform arithmetic operation in two variables .
git branch -r | while read brname ; do
REV_COMMITS=`git rev-list --count $brname`
echo "$brname has $REV_COMMITS"
(( TOTAL = TOTAL + REV_COMMITS ))
echo "in loop" $TOTAL
done
echo "total is " $TOTAL
... (3 Replies)
I have to do some arithmetic operation on Field 8 which is calculated by Field 9/Field 7
Suppose i have data like :
0800123456|JAN|2017|JAN|2018|0800123456|0|0.0000|0.00|
0800234567|JAN|2017|JAN|2018|0800234567|4|2.5812|10.32|
0800666666|JAN|2017|JAN|2018|0800666666|2|1.7255|3.45|... (0 Replies)
Discussion started by: pumrao
0 Replies
LEARN ABOUT MOJAVE
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD