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Top Forums Shell Programming and Scripting how to find out the home directory of a user?? Post 302183153 by danmero on Tuesday 8th of April 2008 12:22:13 PM
Old 04-08-2008
awk only
Code:
awk -F: -v v="user" '{if ($1==v) print $6}' /etc/passwd


Last edited by danmero; 04-08-2008 at 01:28 PM..
 

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XCAL_CAL(1)						      General Commands Manual						       XCAL_CAL(1)

NAME
xcal_cal - interface to calendar(1) for xcal SYNOPSIS
xcal_cal [ -d directory ] [ -f file ] [ -m ] [ -# ] DESCRIPTION
Xcal_cal reads through the files created by xcal(1) and creates a file suitable for use by calendar(1). By default, the files are found in a directory named ``Calendar'' in the user's home directory; an alternate directory may be specified with the -d flag. Output goes by default into a file named ``.xcal'' in the user's home directory; it may be overridden with the -f flag. In both cases, if the argument given begins with a slash (`/'), then it will be taken as a full path name, not as a path relative to the user's home direc- tory. If the argument begins with the two character sequence `./' then it will be taken relative to the current directory. This last form is primarily intended for use while debugging. The -m flag directs that multi-line entries in xcal files be collected in their entirety. By default, only the first line is copied. SEE ALSO
xcal(1),xcalev(1),xcalpr(1) AUTHOR
Ed Gould, Mt.Xinu. Thanks Ed. XCAL_CAL(1)
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