01-25-2008
In vi:
:%s#\/opt\/usr#\/home\/reddy\/dump#g
QED! (quite easily done!)
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
hey
how can i change part of a file
i hve to do in a masses so mv or cp is not practical.
I have to change xxx_rrr to xxx_yyy
pls help
thank (2 Replies)
Discussion started by: ajaya
2 Replies
2. Shell Programming and Scripting
I was using the following code to replace the path names and it works when it is
echo "$PWD/$f" | sed -e 's/^.*chris\.domain\.com/chris.domain.com/'
IN fact it works great
However I tried to incorporate a variable
echo "$PWD/$f" | sed -e... (3 Replies)
Discussion started by: chrchcol
3 Replies
3. Shell Programming and Scripting
Input file - tmp
<begin>
./00003/
./00004/
<end>
I would like to replace "." with the value of pwd
so that the output will look like
/dev/project/00003/
t=`pwd`
sed -e "s/\./$t/g" tmp > tmp1;
The above piece of code is not working. Appreciate your help. (4 Replies)
Discussion started by: lotto_123
4 Replies
4. Shell Programming and Scripting
Hi Guys,
I am needing some help writing a shell script to replace the following in a text file
/opt/was/apps/was61
with some other path eg
/usr/blan/blah/blah.
I know that i can do it using sed or perl but just having difficulty writing the escape characters for it
All Help... (3 Replies)
Discussion started by: cgilchrist
3 Replies
5. Shell Programming and Scripting
Hi all, I want to perform different operations on text like converting string to lower, converting to upper, extract string etc.
can anyone suggest me shell commands for these?
is it possible to take input with read command and then applying perl commands for string manipulation?
Help me. (3 Replies)
Discussion started by: admc123
3 Replies
6. Shell Programming and Scripting
ok, so i have the following text to replace but it's not working. can someone please help me out:
:%s~awk '// {split($2,s,",");a=$1 FS s} /-/ {b=a} END{print b}'~tail -1~g
I want to replace the entire awk command with tail -1.
thanks (7 Replies)
Discussion started by: SkySmart
7 Replies
7. Shell Programming and Scripting
I have file like this
"copy table_name from filea.txt on node replace delimiter '|';"
"copy table_name from fileb.txt on node replace delimiter '|';"
"copy table_name from filec.txt on node replace delimiter'|';"
"copy table_name from filee.txt on node replace delimiter '|';"
"copy... (1 Reply)
Discussion started by: nnani
1 Replies
8. Shell Programming and Scripting
I would like to replace ], with ]]], between /* SECTION2-BEGIN */ and /* SECTION2-END */ in my file. My file contains the following information:
/* SECTION1-BEGIN */
,
/* SECTION1-END */
/* SECTION2-BEGIN */
,
/* SECTION2-END */
/*... (5 Replies)
Discussion started by: azdps
5 Replies
9. Shell Programming and Scripting
hi
i have a requirement to replace a string with another using sed and to get the result newline separated but after sed replacement the newline vanishes
below is sample code
#!/bin/ksh
set -x
string="name sam\nage 45 \nsport soccer"
echo $string
string=`echo $string | sed... (2 Replies)
Discussion started by: midhun19
2 Replies
10. Shell Programming and Scripting
Hello Gurus,
I have a filesystem like below :
/u03/oracle/EBSDEV/fs1/EBSapps/appl
I want to get only the portion of the above text like below...
/u03/oracle/EBSDEV
Can you please advice on this?
Thanks-
P (5 Replies)
Discussion started by: pokhraj_d
5 Replies
LEARN ABOUT DEBIAN
dpkg::changelog::parse
Dpkg::Changelog::Parse(3) libdpkg-perl Dpkg::Changelog::Parse(3)
NAME
Dpkg::Changelog::Parse - generic changelog parser for dpkg-parsechangelog
DESCRIPTION
This module provides a single function changelog_parse() which reproduces all the features of dpkg-parsechangelog.
Functions
my $fields = changelog_parse(%opt)
This function will parse a changelog. In list context, it return as many Dpkg::Control object as the parser did output. In scalar context,
it will return only the first one. If the parser didn't return any data, it will return an empty in list context or undef on scalar
context. If the parser failed, it will die.
The parsing itself is done by an external program (searched in the following list of directories: $opt{libdir},
/usr/local/lib/dpkg/parsechangelog, /usr/lib/dpkg/parsechangelog) That program is named according to the format that it's able to parse. By
default it's either "debian" or the format name lookep up in the 40 last lines of the changelog itself (extracted with this perl regular
expression "schangelog-format:s+([0-9a-z]+)W"). But it can be overridden with $opt{changelogformat}. The program expects the content of
the changelog file on its standard input.
The changelog file that is parsed is debian/changelog by default but it can be overridden with $opt{file}.
All the other keys in %opt are forwarded as parameter to the external parser. If the key starts with "-", it's passed as is. If not, it's
passed as "--<key>". If the value of the corresponding hash entry is defined, then it's passed as the parameter that follows.
1.16.15 2014-06-05 Dpkg::Changelog::Parse(3)