Using the date command
how do get yesterday's date??
e.g.
date '+%b%e%Y'
July 30 2002
I need to get
July 29 2002
using the date command.
Thanx
(p.s. sorry if it's a very obvious question) (6 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hi All.
I'm using date -a to 'drift' the time forward / backwards. The question is - how do I know when its finished 'drifting' ? On some systems I have another time reference I can use but not always.
thanks (1 Reply)
Hi is it possible to give the date command like 24th July 2009
ive tried
DATE=`date "+%d%m%Y"
echo $DATE
that only replies 2009 correctly. not sure how to display the month in full or if unix knows how to do i.e 2nd, 24th, 3rd (1 Reply)
Hi
I want to get tomorrow and yesterday date from date command. My shell is KSH and server is AIX. I tried several options, but unable to do. Please help on this.
Regards
Rajesh (5 Replies)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)