10-26-2007
Quote:
Originally Posted by
oly_r
This returns the size of the array, how do i access the value of a[0]
---
Code:
awk '$0="request -p "$6" -m li -v" $11" path"' FS="[ .]" filename
This doesn't work on my system at all it errors. The FS option doesn't say what it is affecting does that mean it should work on all entries. Also aren't there supposed to be braces ({}) around the awk script. what is the $0 supposed to give me, it looks like it is creating a string variable. Am i supposed to put this in the place of the awk string I showed originally?
It works as expected with GNU Awk, nawk and POSIX (xpg) awk.
Coud you post the error message(s)?
This User Gave Thanks to radoulov For This Post:
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