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Top Forums Shell Programming and Scripting replacing a number with random variable inside shell script Post 302135614 by user_prady on Tuesday 11th of September 2007 02:30:16 AM
Old 09-11-2007
Quote:
Originally Posted by Ygor
Try...
Code:
$ cat file1
NopTX
----Nop(@100); //1
Nop(90); //2
--Nop(80); //3
@Nop(70); //4
--@Nop(60); //5
@Nop@(@50); //6
--Nop@( 40); //7
Nop(@-30); //8

$ awk -F '\\([-@ ]*|\\)' 'NF==3{sub($2,$2*5)};1' file1
NopTX
----Nop(@500); //1
Nop(450); //2
--Nop(400); //3
@Nop(350); //4
--@Nop(300); //5
@Nop@(@250); //6
--Nop@( 200); //7
Nop(@-150); //8


Cool Dude......Thanks for your kind help..
Regards,
PaddySmilie

Last edited by user_prady; 09-14-2007 at 07:36 AM..
 

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