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Top Forums Shell Programming and Scripting How to find the first day of previous month in unix? Post 302124768 by mohapatra on Monday 2nd of July 2007 01:49:55 PM
Old 07-02-2007
Thanks a lot for providing the solution . .But i want some problems as described below.


set -A lastmo $(datecalc -a $(date "+%Y %m") 1 - 1)
lastmo[2]=1
printf "%04d%02d%02d\n" ${lastmo[*]}

-> How can i modify so that the output will be in mmddyyyy format .



THIS_MONTH=`date +%m`
THIS_YEAR=`date +%Y`

LAST_MONTH=`expr $THIS_MONTH - 1`
if [ $LAST_MONTH = 0 ]
then
LAST_MONTH=12
THIS_YEAR=`expr $THIS_YEAR - 1`
fi

cal $LAST_MONTH $THIS_YEAR | head -3 | tail -2

-> the output should be in mmddyyyy format as well...

Can somebody please help .
 

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CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
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