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Top Forums Shell Programming and Scripting accessing variables declared in another perl script Post 302095741 by cbkihong on Thursday 9th of November 2006 08:22:04 PM
Old 11-09-2006
As I said, I used exactly the same case you provided but I got the result you asked for. I'm not sure what your problem is exactly.

Code:
[bernardchan@bernardchan shm]$ cat a.pl
$ENV{a}="20";
system("perl called.pl");
[bernardchan@bernardchan shm]$ cat called.pl
print "$ENV{a}\n";
[bernardchan@bernardchan shm]$ perl -w a.pl
20

 

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MAKESH(1)						      General Commands Manual							 MAKESH(1)

NAME
makeSH - a .SH script maker SYNOPSIS
makeSH files DESCRIPTION
MakeSH examines one or more scripts and produces a .SH file that, when run under sh, will produce the original script. The .SH script so produced has two sections containing code destined for the output. The first section has variable substitutions performed on it (taking values from config.sh), while the second section does not. MakeSH does not know which variables you want to have substituted, so it puts the whole script into the second section. It's up to you to insert any variable substitutions in the first section for any values you want from config.sh. You should run makeSH from within your top-level directory and use the relative path to the file as an argument, so that the "Extracting ..." line printed while running the produced .SH file later on will give that same path. AUTHOR
Larry Wall <lwall@netlabs.com> SEE ALSO
pat(1), metaconfig(1), makedist(1). BUGS
It could assume that variables from metaconfig's Glossary need to be initialized in the first section, but I'm too lazy to make it do that. LOCAL MAKESH(1)
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