10-27-2006
Thanks for the answer, but since I am very unexperienced with UNIX and programing I dont really understand how to proceed with the following commands.
for filename in `cat somefile`
do
ls -lc $filename >> somefile2
done
mv somefile2 somefile
Should I write this in a script? In that case I don't really now how to do it, can u possibly give un example.
Sorry for my low level of understanding....
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I need help to further reduce the output shown below. I want to be able to only return the paragraph where the 'Database alias' is exactly equal to DBIHP. I do not want the other paragraphs being shown below.
$ echo $dbalias
DBIHP
$ db2 list db directory|grep -p 'Database alias ... (2 Replies)
Discussion started by: priceb
2 Replies
2. UNIX for Dummies Questions & Answers
On our one HP-UX 11i box, we have some very long paths defined. When I want to check on our user processes running, the resulting paths are chopped off. /xyz/abc/123/......./server/b is really a process running in the ..../server/bin directory. Is this a terminal problem or buffer length... (1 Reply)
Discussion started by: bsp18974
1 Replies
3. Shell Programming and Scripting
Hi All,
I'm struggling with a problem that I'm wondering (and hoping!) that someone can help me with.
I have a number of .xml files which I'm using grep to search for the string 'include'. I need to extract the value of the include from the grep result.
For example, on any given file, I... (2 Replies)
Discussion started by: Steve_altius
2 Replies
4. Shell Programming and Scripting
Here is one I am baffled with; I have not used unix for a while and now that I am back it has been fun remembering and I have enjoyed it, for the most past. this is in ksh.
I need to search in a file for the line with X1 and cut columns 20-25, put them into a variable, added them (dollar... (3 Replies)
Discussion started by: CougarMutt
3 Replies
5. Shell Programming and Scripting
Hello guys,
I have been looking around but can't find the answer to my problem:
If the grep command displays no results, print "no results have been found" and increment x. But if the grep command find something, do nothing.
if
echo "no results have been found $x"
x=`expr $x + 1 `... (3 Replies)
Discussion started by: Benou
3 Replies
6. UNIX for Dummies Questions & Answers
Hi,
Am running the command below to search for files that contains a certain string.
grep -il "shutdown" `find . -type f -mtime -1 -print` | grep "^./scripts/active"
How do I get it to do a ls -l on the list of files? I tried doing ls -l `grep -il "shutdown" `find . -type f -mtime -1... (5 Replies)
Discussion started by: newbie_01
5 Replies
7. Shell Programming and Scripting
Hi all,
I'm working with a peice of software that runs on Linux that allows planning trips in cars through maps. This software has different variations depending on the type of car, e.g. BMW, Audi, Hyundai, etc... Each variation has a dependency on common external components that are not... (1 Reply)
Discussion started by: emoshaya
1 Replies
8. UNIX for Dummies Questions & Answers
Version: RHEL 5.8
I am doing a grep of the piped output from ps command as shown below.
I am grepping for the pattern ora_dbw* . But, in the result set I am seeing strings with ora_dbr* as well like ora_dbrm_SDLM1DAS3 as shown below. Any idea why is this happening ?
$ ps -ef | grep... (6 Replies)
Discussion started by: John K
6 Replies
9. Shell Programming and Scripting
hi,
let's say we have input in files test1.txt, test2.txt, text3.txt ... ... ... ('...' means more files & lines not just 'dots')
test1.txt has:
A
B
C
D
...
...
...
test2.txt has
A
B
C
D
...
...
... (4 Replies)
Discussion started by: msonoth
4 Replies
10. Shell Programming and Scripting
Hi,
i have a file hello.log which as several line that look like the below
2015-12-07 09:46:56 0:339 120.111.12.12 POST /helloWorld
2015-12-07 09:46:57 0:439 122.111.12.12 POST /helloWorld
....
when i grep expecting to see results like the below.
... (6 Replies)
Discussion started by: mohtashims
6 Replies
LEARN ABOUT MOJAVE
gendiff
GENDIFF(1) General Commands Manual GENDIFF(1)
NAME
gendiff - utility to aid in error-free diff file generation
SYNOPSIS
gendiff <directory> <diff-extension>
DESCRIPTION
gendiff is a rather simple script which aids in generating a diff file from a single directory. It takes a directory name and a "diff-
extension" as its only arguments. The diff extension should be a unique sequence of characters added to the end of all original, unmodi-
fied files. The output of the program is a diff file which may be applied with the patch program to recreate the changes.
The usual sequence of events for creating a diff is to create two identical directories, make changes in one directory, and then use the
diff utility to create a list of differences between the two. Using gendiff eliminates the need for the extra, original and unmodified
directory copy. Instead, only the individual files that are modified need to be saved.
Before editing a file, copy the file, appending the extension you have chosen to the filename. I.e. if you were going to edit somefile.cpp
and have chosen the extension "fix", copy it to somefile.cpp.fix before editing it. Then edit the first copy (somefile.cpp).
After editing all the files you need to edit in this fashion, enter the directory one level above where your source code resides, and then
type
$ gendiff somedirectory .fix > mydiff-fix.patch
You should redirect the output to a file (as illustrated) unless you want to see the results on stdout.
SEE ALSO
diff(1), patch(1)
AUTHOR
Marc Ewing <marc@redhat.com>
4th Berkeley Distribution Mon Jan 10 2000 GENDIFF(1)