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Top Forums UNIX for Dummies Questions & Answers convert from an integer to a string Post 1783 by PxT on Thursday 29th of March 2001 01:45:24 PM
Old 03-29-2001
Ok, makes more sense now. Of course all this could be simplified to:


j = sprintf(buffer,"\tString: %s\n\tCharacter %c\n\tInteger: %d\n\tReal: %f\n",s, c, i, fp);
printf( "Output:\n%s\ncharacter count = %d\n", buffer, j );
 

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A64L(3) 						     Linux Programmer's Manual							   A64L(3)

NAME
a64l, l64a - convert between long and base-64 SYNOPSIS
#include <stdlib.h> long a64l(char *str64); char *l64a(long value); DESCRIPTION
These functions provide a conversion between 32-bit long integers and little-endian base-64 ASCII strings (of length zero to six). If the string used as argument for a64l() has length greater than six, only the first six bytes are used. If longs have more than 32 bits, then l64a() uses only the low order 32 bits of value, and a64l() sign-extends its 32-bit result. The 64 digits in the base 64 system are: '.' represents a 0 '/' represents a 1 0-9 represent 2-11 A-Z represent 12-37 a-z represent 38-63 So 123 = 59*64^0 + 1*64^1 = "v/". NOTES
The value returned by a64l() may be a pointer to a static buffer, possibly overwritten by later calls. The behaviour of l64a() is undefined when value is negative. If value is zero, it returns an empty string. These functions are broken in glibc before 2.2.5 (puts most significant digit first). CONFORMING TO
XPG 4.2, POSIX 1003.1-2001. SEE ALSO
uuencode(1), itoa(3), strtoul(3) 2002-02-15 A64L(3)
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