UNIX for Dummies Questions & Answers

I am using Unix on Mac OS X 10.5.6.

I am trying to extract the last entry of a log (text) file. As seen below, each log entry looks like the following (date and time change with each log entry):

I want the script to extract everything quoted above, including the "===" dividers.

Currently the script I use is the following:

Code:

#! /bin/bash 
tail -n 60 /Library/Logs/CCC.log | mail -s "CCC Log" "myemailaddress"

I'm sure there is a more elegant way to extract the text I want so that I can pipe it into the mail command.

Any help you can provide would be greatly appreciated.

Can try this one:

Code:

sed '/^===\+ Carbon .*===\+$/,/^=\+[[:space:]]*$/!d' infile

You have a blank at the end of the last separator line so I included that [[:space:]]* to make sure it get's it.

Thanks for your help!

I want to make sure I understand what is going on: sed will send to STDOUT the block of text beginning with "==== Carbon" and ending with "===== " (and everything in between from the input file /Library/Logs/CCC.log.

What I don't understand is how sed knows to start at the end of CCC.log (where the latest log entry would be) and how sed knows it is supposed to send one log entry and not every log entry. I have a feeling it has something to do with !d at the end of the command but could not find anything in the man page.

Thanks again for your help.

Code:

#! /bin/bash 
sed '/^===\+ Carbon .*===\+$/,/^=\+[[:space:]]*$/!d' /Library/Logs/CCC.log | mail -s "CCC Log" "myemailaddress"