UNIX for Dummies Questions & Answers

Hi all,

We have an existing script:
find /u03/oraprod/perpcomn/admin/out -type f -ctime +7 \
-exec cp {} "/u08/oraprod/backup/cout" \;

Which is to find all files more than 7 days and copy to another folder. However I would like to only list files with Sep 29, and cp to another folder.

How can I modify to do so? Thx in advance.

Code:

find /u03/oraprod/perpcomn/admin/out -type f -ctime +7 -a -mtime -8 -exec cp {} "/u08/oraprod/backup/cout" \;

I am not 100% sure if it hits your needs but you can play around with it with just a -print instead of -exec to see if it is the result you await.

-a for and
-mtime -8 to limit the time allowed

If it won't work no matter what you do, you might want to exec a ls -l and grep the date out of the long directory listing and xarg it into cp for example.

Please note that the full iso standard file listing is required to successfully execute the following.

Full ISO listing can be accessed via the "ls" command-line option per the following:

U**X: -E
Linux: --full

Please substitute one of the above in the code below under the variable $ISOLISTING

$SOURCEDIR and $DESTDIR should be obvious.

A little messy, but it works.

Code:

(cd $SOURCEDIR ; tar -cf -  `find . -type f -exec ls $ISOLISTING {} \; | grep 2008-09-29 | awk ' { print $9 }'` ) | (cd $DESTDIR ; tar -xpvBf -)